Answered: n this example, we will analyze the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Concept explainers

Question

In this example, we will analyze the motion of an electron that is released in an electric field. The terminals of a 100 VV battery are connected to two large, parallel, horizontal plates 1.0 cmcm apart. The resulting charges on the plates produce an electric field in the region between the plates that is very nearly uniform and has magnitude E� = 3.0×10⁴ N/C. Suppose the lower plate has positive charge, so that the electric field is vertically upward, as shown in (Figure 1). (The thin pink arrows represent the electric field.) If an electron is released from rest at the upper plate, what is its speed just before it reaches the lower plate? How much time is required for it to reach the lower plate? The mass of an electron is me=9.11×10−31kg. Please refer to the photos

In this example, we will analyze the motion of an electron that is
released in an electric field. The terminals of a 100 V battery are
connected to two large, parallel, horizontal plates 1.0 cm apart.
The resulting charges on the plates produce an electric field E in
the region between the plates that is very nearly uniform and has
magnitude E = 3.0x104 N/C. Suppose the lower plate has
positive charge, so that the electric field is vertically upward, as
shown in (Figure 1). (The thin pink arrows represent the electric
field.) If an electron is released from rest at the upper plate, what is
its speed just before it reaches the lower plate? How much time is
required for it to reach the lower plate? The mass of an electron is
me = 9.11 × 10-³1 kg.
Figure
100 V
The thin arrows represent
the uniform electric field.
E
III
F=-eE 1.0 cm
+
1 of 1
>
Finally, vy =
We want to find vy when y = 0.010 m. The equation for vy gives
Voy
+ ayt gives the total travel time t:
Part A - Practice Problem:
|v| =
Submit
Value
ay
Vy
Request Answer
Units
=
=
t=
me
9.11×10 -31 kg
?
REFLECT The acceleration produced by the electric field is enormous; to give a 1000 kg car this acceleration, we would need a force of about 5x1018 N, or about
5x1014
tons. The effect of gravity is negligible. Note again that negative charges gain speed when they move in a direction opposite to the direction of the electric
field.
=+5.27 IU¯¯ m/s¯.
√2ayy=√√2(5.27 × 10¹5 m/s²) (0.010 m)
1.0 × 107 m/s.
Vy-Voy
ay
In this example, suppose a proton (m² = 1.67 × 10−27 kg) is released from rest at the positive plate. What is its speed just before it reaches the negative plate?
Express your answer with the appropriate units.
µÅ
1.0x107 m/s-0
5.27×10¹5 m/s²
-
1.9 × 10-⁹ S.
Constants

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions