→ 2B is a first-order elementary reaction. The reaction is to 10) The liquid-phase reaction A take place in a 300-L constant volume batch reactor that is initially charged with 5 mol/L A. Under the reaction conditions, the kinetic rate constant, kA = 0.825 h¹. a. Determine the time that it will take (in hours) to consume 95% of species A. =-YA STAV dNA ㄧˊ dt Sort = dt SNA CNA ANA -VA-KACA try: CA=CAO (1-x) NAO VAV NA ANA UNA KANA t = √ NA t= ANA -VAV dNA 1 (In NAO-INNA) NA KAIN 300=60m 5 mol In 3.63h 0.825 0.05 b. What will be the concentration of species A (in mol/L) after one hour? 300 = 60 mol 5mol Gomol 3.63h 16.52 mol/h Can't go up Amajn

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Problem 1.1P
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→ 2B is a first-order elementary reaction. The reaction is to
10) The liquid-phase reaction A
take place in a 300-L constant volume batch reactor that is initially charged with 5 mol/L A.
Under the reaction conditions, the kinetic rate constant, kA = 0.825 h¹.
a. Determine the time that it will take (in hours) to consume 95% of species A.
=-YA STAV
dNA
ㄧˊ
dt
Sort = dt SNA
CNA ANA
-VA-KACA
try: CA=CAO (1-x)
NAO VAV
NA ANA
UNA KANA
t = √ NA
t=
ANA
-VAV
dNA 1 (In NAO-INNA)
NA KAIN
300=60m
5 mol
In
3.63h
0.825
0.05
b. What will be the concentration of species A (in mol/L) after one hour?
300
= 60 mol
5mol
Gomol
3.63h
16.52 mol/h Can't go up
Amajn
Transcribed Image Text:→ 2B is a first-order elementary reaction. The reaction is to 10) The liquid-phase reaction A take place in a 300-L constant volume batch reactor that is initially charged with 5 mol/L A. Under the reaction conditions, the kinetic rate constant, kA = 0.825 h¹. a. Determine the time that it will take (in hours) to consume 95% of species A. =-YA STAV dNA ㄧˊ dt Sort = dt SNA CNA ANA -VA-KACA try: CA=CAO (1-x) NAO VAV NA ANA UNA KANA t = √ NA t= ANA -VAV dNA 1 (In NAO-INNA) NA KAIN 300=60m 5 mol In 3.63h 0.825 0.05 b. What will be the concentration of species A (in mol/L) after one hour? 300 = 60 mol 5mol Gomol 3.63h 16.52 mol/h Can't go up Amajn
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