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k1 → k2 15 pts.) 8) Consider the set of liquid phase, elementary series reactions A B C to be carried out in a 10 L batch reactor. The reaction occurs at 300K, where k₁ = 0.6 h¹ and k₂ = 0.25 h¹. The reaction starts with 4 mol/L pure A. a) Calculate the maximum concentration of B (CBmax) and the time it takes to reach that concentration (tmas). 3 species: A,B,C dt MB: dCA =rA dCB=rb dcc= at at =rc 0.6h1 0.25 0.6h-1 10.25-0.6 10.6)0.25-1 (0.25/tmax= (Bmax (0.1") (0.6h") [_ (0°2017- свтах 0.25h-1 Just need to solve this Ki KI K2-KI K2 K2-Ki (Bmax = RICA (KL)² - (11) K K K2-14 b) Calculate CA, CB, and Cc after 4 hours. -Kit CBmax √o.bah' (0.25h) tmax=2√15 -2 h 3 - KICA 2√ kyk₂ +ki+kz сво CA = Amol/L Pure A = CBo CAOC CA-YA dCB=rb dcc=rc CH dt at YA=KACA -rij=kij f YAYB |- rc = -0.6h (4h) - CA Amol/Le CBA CB = K₁CA | e-Kit - e-k₂t 257 CB = (0.6h) (4ml) e-oh (4)/2 = 10.25 (4) [e-0. e-0.6h-1 0.25-1 CAO [K2 (1-e-kit) - ki(1-e-k₂+), = VB = XC CC = K₂cki ==

k1 → k2 15 pts.) 8) Consider the set of liquid phase, elementary series reactions A B C to be carried out in a 10 L batch reactor. The reaction occurs at 300K, where k₁ = 0.6 h¹ and k₂ = 0.25 h¹. The reaction starts with 4 mol/L pure A. a) Calculate the maximum concentration of B (CBmax) and the time it takes to reach that concentration (tmas). 3 species: A,B,C dt MB: dCA =rA dCB=rb dcc= at at =rc 0.6h1 0.25 0.6h-1 10.25-0.6 10.6)0.25-1 (0.25/tmax= (Bmax (0.1") (0.6h") [_ (0°2017- свтах 0.25h-1 Just need to solve this Ki KI K2-KI K2 K2-Ki (Bmax = RICA (KL)² - (11) K K K2-14 b) Calculate CA, CB, and Cc after 4 hours. -Kit CBmax √o.bah' (0.25h) tmax=2√15 -2 h 3 - KICA 2√ kyk₂ +ki+kz сво CA = Amol/L Pure A = CBo CAOC CA-YA dCB=rb dcc=rc CH dt at YA=KACA -rij=kij f YAYB |- rc = -0.6h (4h) - CA Amol/Le CBA CB = K₁CA | e-Kit - e-k₂t 257 CB = (0.6h) (4ml) e-oh (4)/2 = 10.25 (4) [e-0. e-0.6h-1 0.25-1 CAO [K2 (1-e-kit) - ki(1-e-k₂+), = VB = XC CC = K₂cki ==

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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k1 → k2 15 pts.) 8) Consider the set of liquid phase, elementary series reactions A B C to be carried out in a 10 L batch reactor. The reaction occurs at 300K, where k₁ = 0.6 h¹ and k₂ = 0.25 h¹. The reaction starts with 4 mol/L pure A. a) Calculate the maximum concentration of B (CBmax) and the time it takes to reach that concentration (tmas). 3 species: A,B,C dt MB: dCA =rA dCB=rb dcc= at at =rc 0.6h1 0.25 0.6h-1 10.25-0.6 10.6)0.25-1 (0.25/tmax= (Bmax (0.1") (0.6h") [_ (0°2017- свтах 0.25h-1 Just need to solve this Ki KI K2-KI K2 K2-Ki (Bmax = RICA (KL)² - (11) K K K2-14 b) Calculate CA, CB, and Cc after 4 hours. -Kit CBmax √o.bah' (0.25h) tmax=2√15 -2 h 3 - KICA 2√ kyk₂ +ki+kz сво CA = Amol/L Pure A = CBo CAOC CA-YA dCB=rb dcc=rc CH dt at YA=KACA -rij=kij f YAYB |- rc = -0.6h (4h) - CA Amol/Le CBA CB = K₁CA | e-Kit - e-k₂t 257 CB = (0.6h) (4ml) e-oh (4)/2 = 10.25 (4) [e-0. e-0.6h-1 0.25-1 CAO [K2 (1-e-kit) - ki(1-e-k₂+), = VB = XC CC = K₂cki ==
Transcribed Image Text:k1 → k2 15 pts.) 8) Consider the set of liquid phase, elementary series reactions A B C to be carried out in a 10 L batch reactor. The reaction occurs at 300K, where k₁ = 0.6 h¹ and k₂ = 0.25 h¹. The reaction starts with 4 mol/L pure A. a) Calculate the maximum concentration of B (CBmax) and the time it takes to reach that concentration (tmas). 3 species: A,B,C dt MB: dCA =rA dCB=rb dcc= at at =rc 0.6h1 0.25 0.6h-1 10.25-0.6 10.6)0.25-1 (0.25/tmax= (Bmax (0.1") (0.6h") [_ (0°2017- свтах 0.25h-1 Just need to solve this Ki KI K2-KI K2 K2-Ki (Bmax = RICA (KL)² - (11) K K K2-14 b) Calculate CA, CB, and Cc after 4 hours. -Kit CBmax √o.bah' (0.25h) tmax=2√15 -2 h 3 - KICA 2√ kyk₂ +ki+kz сво CA = Amol/L Pure A = CBo CAOC CA-YA dCB=rb dcc=rc CH dt at YA=KACA -rij=kij f YAYB |- rc = -0.6h (4h) - CA Amol/Le CBA CB = K₁CA | e-Kit - e-k₂t 257 CB = (0.6h) (4ml) e-oh (4)/2 = 10.25 (4) [e-0. e-0.6h-1 0.25-1 CAO [K2 (1-e-kit) - ki(1-e-k₂+), = VB = XC CC = K₂cki ==
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