27. A common housefly (Musca domestica) in a top corner of a 7.0 m X 10.0 m × 3.5 m room walks to the lowest opposite corner of the room. a. What will be the magnitude of its net displacement after its epic trip? b. If the fly walks only along the edges of the room, what is the shortest distance it must walk? c. If it is not restricted to the edges, what is the distance of the most direct route the fly must walk to reach its destination? d. Name the surfaces that the fly crosses in Part c.

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Chapter1: Units, Trigonometry. And Vectors
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027. A common housefly (Musca domestica) in a top corner of a
7.0 m X 10.0 m X 3.5 m room walks to the lowest opposite
corner of the room.
a. What will be the magnitude of its net displacement after
its epic trip?
b. If the fly walks only along the edges of the room, what is
the shortest distance it must walk?
c. If it is not restricted to the edges, what is the distance
of the most direct route the fly must walk to reach its
destination?
d. Name the surfaces that the fly crosses in Part c.
Transcribed Image Text:027. A common housefly (Musca domestica) in a top corner of a 7.0 m X 10.0 m X 3.5 m room walks to the lowest opposite corner of the room. a. What will be the magnitude of its net displacement after its epic trip? b. If the fly walks only along the edges of the room, what is the shortest distance it must walk? c. If it is not restricted to the edges, what is the distance of the most direct route the fly must walk to reach its destination? d. Name the surfaces that the fly crosses in Part c.
1:57 1
D)
27
dimensions of room = 7 m ,
10 т,
3.5 m
Initial positiom of house fly
top corner of the
Final position of house fly
= lowest opposite co
a
magnitude of its net displacement =
/(7)² + (
V49 + 100 + 12. 25
/161. 25 m
= 12.7 m
shortest dis tan ce that the fly must walk along ti
= 20. 5 m
If housefly is not restricted to edge, then the di:
the fly must walk to reach its destination = dia
|(3.5)² + (7)² + 10 m
= 7.82 + 10 m
= 17. 82 m
[?
Transcribed Image Text:1:57 1 D) 27 dimensions of room = 7 m , 10 т, 3.5 m Initial positiom of house fly top corner of the Final position of house fly = lowest opposite co a magnitude of its net displacement = /(7)² + ( V49 + 100 + 12. 25 /161. 25 m = 12.7 m shortest dis tan ce that the fly must walk along ti = 20. 5 m If housefly is not restricted to edge, then the di: the fly must walk to reach its destination = dia |(3.5)² + (7)² + 10 m = 7.82 + 10 m = 17. 82 m [?
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