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Chag 5 I Beno with mass of 8o ky Pushed along tlat ground. AMe-0,2 Men. | hano 38A knA, what does prano wegh? o4313.63. what force needed to get it to move? 156.&C. What force To keer t moring at canstant velocity? grovad. Mx-0,2 My-D; Cut seely To gt T acceler ate at 5ml"2

Chag 5 I Beno with mass of 8o ky Pushed along tlat ground. AMe-0,2 Men. | hano 38A knA, what does prano wegh? o4313.63. what force needed to get it to move? 156.&C. What force To keer t moring at canstant velocity? grovad. Mx-0,2 My-D; Cut seely To gt T acceler ate at 5ml"2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Worksheet Answers and Explanations** **Chapter 5: Forces and Motion** 1. **Piano with mass of 80 kg pushed along flat ground (\( \mu_k = 0.2, \mu_s = 0.3 \)):** - a. **Weight of the piano:** 784 N - b. **Force needed to get it to move:** 313.6 N - c. **Force to keep it moving at constant velocity:** 156.8 N - d. **Force to apply to get it to accelerate at 5 m/s²:** 278.8 N 2. **120 kg box on concrete ground. Workers pull at combined force of 800 N parallel to ground (\( \mu_k = 0.8, \mu_s = 0.5 \)):** - Can the workers move the box? **No** - **Why?** A force greater than 940.8 N is needed to get the box moving. 3. **Object with mass of 65 kg on inclined plane at 28° to horizontal:** - A force of 35 N is applied up the plane. The object accelerates at 2.5 m/s². - Determine \( \mu_k \) between object and plane: \( \mu_k = 0.31 \) 4. **70 kg person sliding down a hill of 50° (\( \mu_k = 0.1 \)):** - How fast is the person going after 2.0 seconds? - Time after 2.0 s: 7.6 m/s² 5. **Perpendicular force component of the weight of a 700,000 N truck resting on a hill angled at 50°:** - Calculate \( F \perp = mg \cos \theta \) - Resulting perpendicular force: 449,645.9 N **Diagram:** - The fourth problem features a diagram illustrating forces acting on an inclined plane. It depicts: - \( \text{mg} \, \cos \theta \) as perpendicular to the slope - \( \text{mg} \, \sin \theta \) along the slope
Transcribed Image Text:**Physics Worksheet Answers and Explanations** **Chapter 5: Forces and Motion** 1. **Piano with mass of 80 kg pushed along flat ground (\( \mu_k = 0.2, \mu_s = 0.3 \)):** - a. **Weight of the piano:** 784 N - b. **Force needed to get it to move:** 313.6 N - c. **Force to keep it moving at constant velocity:** 156.8 N - d. **Force to apply to get it to accelerate at 5 m/s²:** 278.8 N 2. **120 kg box on concrete ground. Workers pull at combined force of 800 N parallel to ground (\( \mu_k = 0.8, \mu_s = 0.5 \)):** - Can the workers move the box? **No** - **Why?** A force greater than 940.8 N is needed to get the box moving. 3. **Object with mass of 65 kg on inclined plane at 28° to horizontal:** - A force of 35 N is applied up the plane. The object accelerates at 2.5 m/s². - Determine \( \mu_k \) between object and plane: \( \mu_k = 0.31 \) 4. **70 kg person sliding down a hill of 50° (\( \mu_k = 0.1 \)):** - How fast is the person going after 2.0 seconds? - Time after 2.0 s: 7.6 m/s² 5. **Perpendicular force component of the weight of a 700,000 N truck resting on a hill angled at 50°:** - Calculate \( F \perp = mg \cos \theta \) - Resulting perpendicular force: 449,645.9 N **Diagram:** - The fourth problem features a diagram illustrating forces acting on an inclined plane. It depicts: - \( \text{mg} \, \cos \theta \) as perpendicular to the slope - \( \text{mg} \, \sin \theta \) along the slope
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