25.10. Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve (find length of curve) and full-station elevations Grades of g1 = -2.50% and g2 = +1.00%, VPI elevation 750.00 ft at station 30+ 00. Fixed elevation 753.00 ft at station 30+ 00.

25.10. Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve (find length of curve) and full-station elevations Grades of g1 = -2.50% and g2 = +1.00%, VPI elevation 750.00 ft at station 30+ 00. Fixed elevation 753.00 ft at station 30+ 00.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A vertical road was designed with three tangent lines having a grade of 7.3%, -3.9 %, and 2.8%, consecutively. The intersections of the three lines are known to be V1 and V2 having an elevation of 226.10m and 202.03m respectively. The said tangent lines will be connected by a summit and a sag unsymmetrical parabolic curve which meets at point A having an elevation of 216.29m above sea level. The L1 of the summit curve is 106.73m and the maximum offset of the sag curve is 0.51 multiplied to the maximum offset of the summit curve. Point A is located at the line that connects the two vertices. What is the elevation at the end of the road in meter?
An equal tangent vertical curve is intended to connect grades of 2.6% and -0.8%. If this curve is to be a part of a highway designed with a PSD of 550ft, determine the minimum length (ft) of the vertical curve. Use exact solution (do not use the table). Round your answer to 3 decimal places.
A crest vertical curve has the following information: L = 160 m, Station PVI = 4 + 310, Elevation PVI = 411 m, Elevation PVC = 407.8 m, Elevation PVT = 409 m, Find (1) Initial and final grades ? (2) Elevation and stationing of the highest point?
NEED ASAP A vertical summit curve is having tangents which intersects at point Pl at station 12+583 and 128.0 meters elevation. The grade for the forward tangent is -5.54%. Station PC is at station 12+530 and having an elevation of 123.744 meters. Determine the value of the maximum offset in meters. Determine grade of back tangent. Determine horizontal length of curve in meters.
Two tangents in profile meet at a vertical point of intersection (VPI). The entrance tangent grade is +5%. The exit tangent grade is -3%. Point on Tangent 1 (POT1) is on the entrance grade. Point on Tangent 2 (POT2) is on the exit grade. An equal tangent vertical curve of 1000.00 ft has been designed to provide a smooth transition between them. Point Station Elevation ft POT1 61+00.00 4900.00 POT 2 242+00.00 4500.00 Elevation of the VPI = O 1) 4773.23 2) 5089.47 3) 4998.45 4) 4941.33 5) 4989.38 6) 5080.00 7) 5118.80 8) none 9) 5087.28 10) 5117.75
Determine variables requested below for a horizontal curve with the following characteristics. Length of curve 1255', Radius 1200', sta of PC 12+00 superelevation rotated about the roadway centerline, 3 lane roadway, 14ft lane width, entire road section normal crown=2%, road design speed=60 mph, max superelevation=8% 3) The Lr of the curve, in ft, is: 77.5 O 310 692 1200 1255
An equal tangent vertical curve is intended to connect grades of 3.5% and -2.9%. If this curve is to be a part of a highway designed with a PSD of 500ft, determine the minimum length (ft) of the vertical curve. Use exact solution (do not use the table).
Question 2 Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations: (Compute L, and the elevations at the full stations). Grades of g₁ = -2.50% and 82 = +1.50%, VPI elevation 2560.00 ft at station 315 +00. Fixed elevation 2567.00 ft at station 314 + 00.
A simple circular curve is designed to connect a single lane highway at PI station 64+27.46 sta. with an interior angle (A) = 8° 24'. The terrain conditions require a minimum radius of 2864.79 ft. Compute the following parameters to complete the design process: 1) The station of PC and PT 2) Tangent length (T) 3) Degree of curvature (D) 4) Long Cord (LC) 5) External and middle ordinate (E & M)
Determine the values and stationing (sta. PT) for a compound curve to be placed on an exist loop of a freeway. The stationing of the loop construction will start at the point the taper departs the freeway with a station of 10+00. The Pl of the compound curve will begin 2,700ft after the taper starts. The first curve has a radius of 2,400ft and a deflection angle of 33° 45' and the second curve has a radius of E (Ctrl) 1,900ft and a deflection angle of 25° 15'.
A vertical curve is to be design to joint (+3) percent grade with a (-3.5) percent grade, sight distance (SSD=120.00 m). The minimum length of the curve equal to: 162.204 m. 150.00 ft/sec.. O 142.422 m. O 467.1982 m. O 154.402 ft.
answer question 21 only