25- 2 H2S(g) → 2 H2(g) + S2(g) When heated, hydrogen sulfide gas decomposes according to the equation above. A 3.40 g sample of H2S(g) is introduced into an evacuated rigid 1.25 L container. The sealed container is heated to 483 K, and 3.72x10-2 mol of S2(g) is present at equilibrium. (a) Write the expression for the equilibrium constant, Ke, for the decomposition reaction represented above. (b) Calculate the equilibrium concentration, in mol·L-l, of the following gases in the container at 483 K. (i) H2(g) (ii) H2S(g) (c) Calculate the value of the equilibrium constant, Ke, for the decomposition reaction at 483 K.

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25- 2 H2S(g) → 2 H2(g) + S2(g)
When heated, hydrogen sulfide gas decomposes according to the equation above. A 3.40 g
sample of H2S(g) is introduced into an evacuated rigid 1.25 L container. The sealed container
is heated to 483 K, and 3.72x10-2 mol of S2(g) is present at equilibrium.
(a) Write the expression for the equilibrium constant, Ke, for the decomposition reaction
represented above.
(b) Calculate the equilibrium concentration, in mol·L-1, of the following gases in the container
at 483 K.
(i) H2(g)
(i) Н2S(g)
(c) Calculate the value of the equilibrium constant, Ko, for the decomposition reaction at 483
K.
(d) Calculate the partial pressure of S2(3) in the container at equilibrium at 483 K.
(e) For the reaction H2(g) + S2(2) –→ H2S(g) at 483 K, calculate the value of the equilibrium
constant, K.
Transcribed Image Text:25- 2 H2S(g) → 2 H2(g) + S2(g) When heated, hydrogen sulfide gas decomposes according to the equation above. A 3.40 g sample of H2S(g) is introduced into an evacuated rigid 1.25 L container. The sealed container is heated to 483 K, and 3.72x10-2 mol of S2(g) is present at equilibrium. (a) Write the expression for the equilibrium constant, Ke, for the decomposition reaction represented above. (b) Calculate the equilibrium concentration, in mol·L-1, of the following gases in the container at 483 K. (i) H2(g) (i) Н2S(g) (c) Calculate the value of the equilibrium constant, Ko, for the decomposition reaction at 483 K. (d) Calculate the partial pressure of S2(3) in the container at equilibrium at 483 K. (e) For the reaction H2(g) + S2(2) –→ H2S(g) at 483 K, calculate the value of the equilibrium constant, K.
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