24.0 24.0 V -5.00 cm-
Q: The coil in the figure carries current i = 2.35 A in the direction indicated, is parallel to an xz…
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Q: The coil in the figure carries current i = 2.48 A in the direction indicated, is parallel to an xz…
A: Current, i = 2.48 A Turns, n = 5 Area, A = 5.47×10-3 m² Field, B = (1.55î - 2.44ĵ - 4.65k̂)×10-3 T…
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A: Given, L=2mv=5 m/sB=0.04TR=3Ω
Q: R = 8.50 Ω, ℓ = 1.40 m, and B = 2.75 T. At what constant speed (in m/s) should the bar be moved to…
A: Given, Resistance, R = 8.50 Ω Length, l = 1.40 m Magnetic field, B = 2.75 T Current, i = 1.60 A i)…
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A: mass= 0.225 Kg L=1.2 m Angle=35 Resistance =2.2 ohms B=0.5 T Mic test…
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A: Given, Resistance , R = 7.00 Ω Length or distance between rails ,l = 1.20 m Magnetic field = 2.50 T…
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Q: I have a physics question as follow "Consider the apparatus shown below in which a conducting bar…
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Q: Consider the arrangement shown in the figure below where R = 8.50 Q, = 1.00 m, and B = 3.00 T. R.…
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A: m=0.043 kgL=1.37 mB=0.74 Tg=9.81 m/s2
Q: to slide on two parallel conducting ba shown in the figure. A resistor R = 5 [ connected across the…
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Q: A current of 5.0 A is maintained in a single circular loop having a circumference of 90 cm. An…
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Q: The slide generator in the figure below is in a uniform magnetic field of magnitude 0.0500 T. The…
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Q: The value of the induced current is:
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Q: The coil in the figure carries current i = 1.71 A in the direction indicated, is parallel to an xz…
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Q: The coil in the figure carries current i = 2.15 A in the direction indicated, is parallel to an xz…
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Q: A conducting rod of length = 7 [cm] is free to slide on two parallel conducting bars as shown in the…
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Q: The coll in the figure carries current i = 1.60 A in the direction indicated, is parallel to an xz…
A: Given data: The current in the coil is i=1.6 A. The number of turns is n=4. Area of coil is…
Q: A conducting rod is free to slide on two parallel conducting bars. A resistor is connected to the…
A: v=Velocity of rod=8 m/sP=Power=64 W
Q: A conducting rod is free to slide on two parallel conducting bars. A resistor is connected to the…
A: given,P=64W=I2R
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Q: At a particular point on Earth, the magnitude of the Earth's magnetic field is 2.50 ✕ 10−5 T. At…
A: Given that the magnetic field is 2.5 × 10-⁵ T. The area of the loop is 40 cm². We have to find the…
Considering the system that appears in the figure, the wires are joined by means of two springs of elastic constant k. Then a small lower wire of m = 15g and ℓ = 5cm is placed that is attached to the two springs and these are stretched Δx = 0: 4cm by action of their weight. Subsequently, the
Current( I) in wire =V/R=24/12=2 Ampere
Now force due to magnetic field in wire will be upward from flaming's right hand rule
And will be equal to BIL
Where B is magnetic field,L is length of wire.
L=0.15 meter
Weight=15 g=0.015 Kg
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