The slide generator in the figure below is in a uniform magnetic field of magnitude 0.0500 T. The bar of length 0.355 m is pulled at a constant speed of 0.500 m/s. The U-shaped conductor and the bar have a resistivity of 2.75 × 10-8 0 · m and a cross-sectional area of 9.75 x 10¬4 m². Find the current in the generator when x = 0.610 m. (Note that the A in the image below is the area of the loop, not the cross-sectional area of the conductor and bar.) 125 X A
The slide generator in the figure below is in a uniform magnetic field of magnitude 0.0500 T. The bar of length 0.355 m is pulled at a constant speed of 0.500 m/s. The U-shaped conductor and the bar have a resistivity of 2.75 × 10-8 0 · m and a cross-sectional area of 9.75 x 10¬4 m². Find the current in the generator when x = 0.610 m. (Note that the A in the image below is the area of the loop, not the cross-sectional area of the conductor and bar.) 125 X A
Related questions
Question

Transcribed Image Text:**Educational Website Content:**
**Understanding Slide Generators in Magnetic Fields**
The slide generator depicted below operates within a uniform magnetic field with a magnitude of 0.0500 T (Tesla). A bar, measuring 0.355 m in length, is pulled at a constant speed of 0.500 m/s. Both the U-shaped conductor and the bar have a resistivity of \(2.75 \times 10^{-8} \, \Omega \cdot \text{m}\) and a cross-sectional area of \(9.75 \times 10^{-4} \, \text{m}^2\). The task is to determine the current generated when the position \(x\) is 0.610 m.
**Figures A and B Description:**
- **Figure A:**
- This diagram shows the initial state where the bulb remains unlit.
- The magnetic field \(\vec{B}\) is directed perpendicular to the plane of the loop.
- The area \(\vec{A}\) of the loop is identified within the figure.
- **Figure B:**
- In this state, the bulb is illuminated, indicating current flow.
- The length \( \ell \) and position \(x\) of the bar are shown.
- The magnetic field \(\vec{B}\) and current \(I\) direction are indicated with arrows.
- A mechanical force \(\vec{F}_{\text{mech}}\) is applied to maintain motion.
- An additional magnetic field \(\vec{B}_{\text{loop}}\) is illustrated for induced effects.
This example illustrates the fundamental principles of electromagnetic induction, showcasing how movement through a magnetic field can generate electrical currents. Calculate the current using the known variables and formulae associated with electromagnetic theory.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images
