24. Professor Sanov runs the reaction in problem 22 and allows it to reach equilibrium at T = 740 K. He then finds the equilibrium concentrations of N₂ and H₂ to be [N₂] = 0.90 Mand [H₂] = 1.0 M. Given that Kc = 10., what is the equilibrium concentration of NH3 in Professor Sanov's experiment? (A) 0.03 (B) 0.10 (C) 0.30 (D) 0.40 (E) 1.0

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24. Professor Sanov runs the reaction in problem 22 and allows it to reach
equilibrium at T = 740 K. He then finds the equilibrium concentrations of N₂ and H₂
to be [N₂] = 0.90 Mand [H₂] = 1.0 M. Given that Kc = 10., what is the equilibrium
concentration of NH3 in Professor Sanov's experiment?
(A) 0.03
(B) 0.10
(C) 0.30
(D) 0.40
(E) 1.0
Transcribed Image Text:24. Professor Sanov runs the reaction in problem 22 and allows it to reach equilibrium at T = 740 K. He then finds the equilibrium concentrations of N₂ and H₂ to be [N₂] = 0.90 Mand [H₂] = 1.0 M. Given that Kc = 10., what is the equilibrium concentration of NH3 in Professor Sanov's experiment? (A) 0.03 (B) 0.10 (C) 0.30 (D) 0.40 (E) 1.0
Consider the reaction:
2 NH3(g)
N₂(g) + 3 H₂(g).
At T = 740 K, the equilibrium constant K for this reaction is Kc = 10.
22. What is the correct form of the equilibrium constant K for this reaction?
3
(A) Kc = [N₂] [H₂]³
(B) Kc =
(C) Kc =
(D) Kc
2[NH3]
[N₂] + 3 [H₂]
=
(E) Kc =
[N₂] + 3[H₂]
2[NH3]
[NH3]²
[N₂] [H₂]³
[N₂] [H₂] ³
[NH3]²
Transcribed Image Text:Consider the reaction: 2 NH3(g) N₂(g) + 3 H₂(g). At T = 740 K, the equilibrium constant K for this reaction is Kc = 10. 22. What is the correct form of the equilibrium constant K for this reaction? 3 (A) Kc = [N₂] [H₂]³ (B) Kc = (C) Kc = (D) Kc 2[NH3] [N₂] + 3 [H₂] = (E) Kc = [N₂] + 3[H₂] 2[NH3] [NH3]² [N₂] [H₂]³ [N₂] [H₂] ³ [NH3]²
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