23. Consider the following hypothesis test:Ho: H12H:p> 12A sample of 25 provided a sample mean x= 14 and a sample standard deviations=4.32.a. Compute the value of the test statistic.b. Use the t distribution table (Table 2 in Appendix B) to compute a range for thep-value.c. At a = .05, what is your conclusion?d. What is the rejection rule using the critical value? What is your conclusion?

Given information Hypothesized mean = 12 Sample Standard deviation = 4.32 Sample mean = 14 Sample…

Answered: 23. Consider the following hypothesis…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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9. A random sample of 25 statistics examinations was taken. The average score in the sample was 76 with a variance of 144. Assuming the scores are normally distributed, the 99% confidence interval for the population average examination score is a. 70.02 to 81.98 b. 69.82 to 82.18 C. 70.06 to 81.94 d. 69.48 to 82.52
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18. Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H1 p< 3/5, the test statistic is z = -1.68
1. The weight (in pounds) for a population of school-aged children is normally distributed with a mean equal to 135 plus-minus 20 pounds (mean & standard deviation). Suppose we select a sample of 100 children to test whether children in this sample have a different weight. Test at the 0.05 level of significance. a. What are the null and alternative hypotheses? b. What is the critical value for this test? c. What is the mean of the sampling distribution? d. What is the standard error of the mean for this distribution?
5. A brochure inviting subscriptions for a new diet program states that the participants are expected to lose over 22 pounds in five weeks. Suppose that, from the data of the five-week weight losses of 56 participants, the sample mean and sample standard deviation are found to be 23.5 and 10.2, respectively. Could the statement in the brochure be substantiated on the basis of these findings? Test at the α = .05 level.
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14 A variable must lie between an upper and lower specification. The distribution of the variable is normal with standard deviation 0.6 mm. Determine the sample size and boundaries of acceptance region such that both of the below conditions are satisfied simultaneously. Condition1: If the population mean is bekow 45mm or above 47 mm the probability of lot acceptance is 10%. Condition2: If the population mean is between 45mm and 47 mm the probability of lot acceptance is 95%.
When is it appropriate to use the pooled two-sample t-methods? Choose the correct answer below. O A. Use the pooled two-sample t-methods when the distribution of the difference in sample means is known to be skewed. O B. Use the pooled two-sample t-methods when the population standard deviations are known. O C. Use the pooled two-sample t-methods when the samples come from populations with different standard deviations. D. Use the pooled two-sample t-methods when the samples come from different populations with the same, or nearly the same, standard deviations.
10. For which of the following cases would you use a t-test statistic? A. Where the population distribution is not normal, the population variance is not known and the sample size is below 25. B. Where the population distribution is not normal but the population variance is known. C. Where the population distribution is normal, the population variance is not known and the sample size is below 25. D. Where the population distribution is normal, the population variance is known and the sample size is 25 or more.
14. The sales price of a specific brand of cereal is believed to be normally distributed. Data were collected for a sample of 16 boxes of that brand of cereal. If the sample mean is 2 OMR and the sample standard deviation is 0.4 OMRthen the 90% confidence interval for the population mean is A. (1.8355 , 2.1645) B. (1.8040 , 2.1960) C. None D. (1.8247 , 2.1753)

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