N5)(ratalaSILO23-A) An activated sludge system is to be used for treatment of 10000 m/day of municipal wastewater. Arimary clarification, the value of BOD, is 150 mg/l, and it is desired to have not more than 5 mg/l. in.ffluent. Assume that Y- 0.5; K, 0.05/day; and ML.VSS-3000 mg/l; Return sludge concentration 10ng/L. 0 10 days. Determine:Treatment efficiency and the volumetric organic loading.3) Microorganism ratio5) The quantity of sludge that must be wasted each day i2) Reactor volume and detention time.4) the recycle ratin

Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

23-A) An activated sludge system is to be used for treatineat of 10000 m'day of municipal wastewater.. rimary clarification, the value of BOD, is 150 mg/l, and it is desired to have not more than 5 mg/l. in ffluent. Assume that Y- 0.5; K,-0.05iday; and MIVSS-3000 mg/l.; Return sludge concentration-1 ng/L. 0,10 days. Determine: Treatment efficiency and the volumetric organic loading. 3) Microorganisms ratio V 5) The quantity of sludge that must be wasted each day 2) Reactor volume and detention time. 4) the recycle ratio

23-A) An activated sludge system is to be used for treatineat of 10000 m'day of municipal wastewater.. rimary clarification, the value of BOD, is 150 mg/l, and it is desired to have not more than 5 mg/l. in ffluent. Assume that Y- 0.5; K,-0.05iday; and MIVSS-3000 mg/l.; Return sludge concentration-1 ng/L. 0,10 days. Determine: Treatment efficiency and the volumetric organic loading. 3) Microorganisms ratio V 5) The quantity of sludge that must be wasted each day 2) Reactor volume and detention time. 4) the recycle ratio

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Find the question, thanx.
In an activated sludge treatment unit with tank volume of 700 m³, the imfluent BOD of the sludge at 4000 m³/day of discharge is 250 mg/lt which reduced to 30 mg/lt in the effluent sludge. The MLVSS concentration in the aeration tank is 3000 mg/lt. The F/M ratio is kg/kg/day.
Two wastewater streams A and B, having an identical ultimate BOD are getting mixed to form the stream C. The temperature of the stream A is 20 °C and the temperature of the stream C is 10 °C. It is given that • The 5-day BOD of the stream A measured at 20 °C=50 mg/l • BOD rate constant (base 10) at 20 °C-0.115 per day Temperature coefficient = 1.135 The 5-day BOD (in mg/l, up to one decimal place) of the stream C, calculated at 10 °C, is ●
wet sludge contains 3% solid by weight is pumped to a filter belt press at the rate of 170,000lb/day. the dewatered sludge is 18% by dry weight and the filtrate has total nitrogen concentration of 100 mg/l as nitrogen. assume the belt press has 100% solid capture and specific gravity of the sludge in all forms is 1. Calculate the amount of nitrogen (lb/day) in the filtrate returned? a) 4 b) 9 c) 14 d) 19
A single media filter has a 720mm deep bed of sand (diameter = 5 x 10^-4 m, shape factor = 0.8). The porosity of the system is 0.40. The filtration rate is 1.2 (L/s)m^2. The water viscosity is 1.14 x 10^-6 m^2/s. A. What is the Reynold’s number of the filter B. What is the friction factor for the filter? C. What is the total clean head loss across the filter in m?
Q1: The design flow for a water treatment plant (WTP) is 1 MGD (3.8x10 m³ /d). The rapid mixing tank will have a mechanical mixer and the average alum dosage will be 30 mg/L. The theoretical mean hydraulic detention time of the tank will be 1 minute. Determine the following: a) the quantity of alum needed on a daily basis in kg/d, b) the dimensions of the tank in meters for a tank with equal length, width, and depth, c) the power input required for a G of 900 sec' for a water temperature of 10 °C. Express the answer in kW, given that u = 1.307 × 10³Kg/m.s.
Need it urgent
An activated sludge wastewater treatment system was designed and operated in a steadystate under the following conditions:• Reactor volume of 10,000 m3in total;• Sludge concentration (MLSS) of 3200 mg/L in the reactor;• Return sludge concentration at 8000 mg/L (the underflow of the secondary clarifier)• Each day, 400 m3 of underflow sludge (return sludge) was wasted as excesssludge;What is the average Sludge Residence Time (SRT)?
Q-The MLSS concentration in an aeration tank is 2000 mg/l and the sludge volume after 30 minutes of setting in a 1000 ml graduated cylinder is 175 ml. Find the value of sludge density index (SDI).
3. A 100 mL of wastewater sample was drying on a 0.5 g empty dish weight at 104 °C to weight 0.5625 g. Another 100 mL of the same wastewater was first filtered and the filtrate was dried on a 0.5 g dish at 104 °C to weight 0.5325 g. Determine in mg/L the:a) TSb) TSSc) TDSd) VSS assuming it represents 70% of TSS
The 750-bed Associated Center of Medical Excellence (ACME) Hospital has a small activated sludge plant to treat its wastewater. The average daily Medical Center discharge is 1,250 L per day per bed, and the average soluble BOD5 after primary settling is 450 mg/L. The aeration tank has effective liquid dimensions of 10.0 m wide by 25.0 m long by 3.5 m deep. The plant operating parameters are as follows: MLVSS = 2,750 mg/L MLSS = 1.25 (MLVSS) Settled sludge volume after 30 min = 250 mL/LDetermine the following: aeration period, F/M ratio, SVI, solids concentration in return sludge.
I need the answer as soon as possible