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22.5 Part D, please

22.5 Part D, please

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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22.5 Part D, please 

The di %001 distributiome onditional The differences atus. of ERT history , cm) a with a was (b) Now the cited into a table. Are per- introduced, the aphids and jelly helped their land- tus? What do they about the between and e they part of the of given sta- sap-sucking that live on (such as ladybugs) Current oral ERT use Never use Past use Current transdermal ERT use APPLY YOUR KNOWLEDGE 22.1 E-cigarettes and smoking cessation. Electronic cigarettes (e-cigarettes) are battery-operated devices that can deliver nicotine and other chemicals in water vapor instead of smoke. They are a relatively recent invention with little scientific evaluation, yet some people believe that e-cigarettes could help smokers who want to quit smoking. Researchers in New Zealand randomly assigned 657 adult smokers wanting to quit to three treatment groups: nicotine patches, nicotine e-cigarettes, and placebo e-cigarettes. Smoking abstinence at the end of the study was assessed biochemically for all participants with a breath analyzer. The published research reports that, “at 6 months, verified abstinence was 7.3% (21 of 289) with nicotine e-cigarettes, 5.8% (17 of 295) with patches, and 4.1% (three of 73) with placebo e-cigarettes."² >> cat- The »2 (a) Organize the study findings in the following two-way table of counts. Add the group totals to your table. SJuno Sjuno Smoking status at six months Total Non-abstinent uch larger Verified abstinence Treatment group ithin each Nicotine e-cigarettes Patches mello Placebo e-cigarettes sn .... ols cents part of the conditional distribution of abstinence, given treatment group, or %S by dcking insects that live on plants, They evade predators (such as ladybugs) ReOpping off the plants. A study examined the mechanism of aphid drops. %2 tim tchers placed aphids on a leaf positioned at four different heights (in cen- timeters, Hereture (upright or not). Each aphid performed this experiment only once. are the findings:
Transcribed Image Text:The di %001 distributiome onditional The differences atus. of ERT history , cm) a with a was (b) Now the cited into a table. Are per- introduced, the aphids and jelly helped their land- tus? What do they about the between and e they part of the of given sta- sap-sucking that live on (such as ladybugs) Current oral ERT use Never use Past use Current transdermal ERT use APPLY YOUR KNOWLEDGE 22.1 E-cigarettes and smoking cessation. Electronic cigarettes (e-cigarettes) are battery-operated devices that can deliver nicotine and other chemicals in water vapor instead of smoke. They are a relatively recent invention with little scientific evaluation, yet some people believe that e-cigarettes could help smokers who want to quit smoking. Researchers in New Zealand randomly assigned 657 adult smokers wanting to quit to three treatment groups: nicotine patches, nicotine e-cigarettes, and placebo e-cigarettes. Smoking abstinence at the end of the study was assessed biochemically for all participants with a breath analyzer. The published research reports that, “at 6 months, verified abstinence was 7.3% (21 of 289) with nicotine e-cigarettes, 5.8% (17 of 295) with patches, and 4.1% (three of 73) with placebo e-cigarettes."² >> cat- The »2 (a) Organize the study findings in the following two-way table of counts. Add the group totals to your table. SJuno Sjuno Smoking status at six months Total Non-abstinent uch larger Verified abstinence Treatment group ithin each Nicotine e-cigarettes Patches mello Placebo e-cigarettes sn .... ols cents part of the conditional distribution of abstinence, given treatment group, or %S by dcking insects that live on plants, They evade predators (such as ladybugs) ReOpping off the plants. A study examined the mechanism of aphid drops. %2 tim tchers placed aphids on a leaf positioned at four different heights (in cen- timeters, Hereture (upright or not). Each aphid performed this experiment only once. are the findings:
output for the chi-square test for the calculator and three statistical programs. All four display the expected rom a SMC graphing the value of the test statistic, X² = 21.268. The chi-square statistic ie nts and statistical though each uses a different terminology: "Cell Chi" 2" for JPM, “Contribuons, Commander. APPLY YOUR KNOWLEDGE experiment comparing three approaches for quitting smoking. Figure 22 3 an the Minitab output for a chi-square test with a null hypothesis of no associari between treatment received and abstinence outcome in the population of smol who want to quit. ar in (a) Show how to obtain the expected counts of smokers with or without verifiel abstinence at six months among those using a nicotine e-cigarette. Your resuls should agree, up to rounding error, with Figure 22.3. Verify that these two expecteid counts add to the row total for the observed counts in the nicotine e-cigarette ch to group. is (b) Compare the observed and expected counts in Figure 22.3. What do they suggest? b. (c) Show how the first chi-square component in the Minitab output (0.48745) was C. computed. (d) What is the value of the chi-square statistic reported by Minitab? Verify that, up to rounding error, this value is the sum of all six chi-square components shown in the Minitab output. l Minitab Chi-Square Test for Association: Treatment, Worksheet columns Rows: Treatment Columns: Worksheet columns Verified abstinence Non-abstinent All Nicotine e-cigarette 21 268 289 18.04 270.96 0.48745 0.03244 Patch 17 278 295 18.41 276.59 0.10791 0.00718 Placebo e-cigarette 3 73 4.56 68.44 0.53117 0.03535 All 41 616 657 Cell Contents: Count Expected count Contribution to Chi-square RE 22.3 Pearson Chi-Square = 1.202, DF = 2, P-Value = 0.548 Likelihood Ratio Chi-Square = 1.253, DF = 2, P-Value = 0.534 square output for the ble of e-cigarettes and * NOTE * 1 cells with expected counts less than 5 essation.
Transcribed Image Text:output for the chi-square test for the calculator and three statistical programs. All four display the expected rom a SMC graphing the value of the test statistic, X² = 21.268. The chi-square statistic ie nts and statistical though each uses a different terminology: "Cell Chi" 2" for JPM, “Contribuons, Commander. APPLY YOUR KNOWLEDGE experiment comparing three approaches for quitting smoking. Figure 22 3 an the Minitab output for a chi-square test with a null hypothesis of no associari between treatment received and abstinence outcome in the population of smol who want to quit. ar in (a) Show how to obtain the expected counts of smokers with or without verifiel abstinence at six months among those using a nicotine e-cigarette. Your resuls should agree, up to rounding error, with Figure 22.3. Verify that these two expecteid counts add to the row total for the observed counts in the nicotine e-cigarette ch to group. is (b) Compare the observed and expected counts in Figure 22.3. What do they suggest? b. (c) Show how the first chi-square component in the Minitab output (0.48745) was C. computed. (d) What is the value of the chi-square statistic reported by Minitab? Verify that, up to rounding error, this value is the sum of all six chi-square components shown in the Minitab output. l Minitab Chi-Square Test for Association: Treatment, Worksheet columns Rows: Treatment Columns: Worksheet columns Verified abstinence Non-abstinent All Nicotine e-cigarette 21 268 289 18.04 270.96 0.48745 0.03244 Patch 17 278 295 18.41 276.59 0.10791 0.00718 Placebo e-cigarette 3 73 4.56 68.44 0.53117 0.03535 All 41 616 657 Cell Contents: Count Expected count Contribution to Chi-square RE 22.3 Pearson Chi-Square = 1.202, DF = 2, P-Value = 0.548 Likelihood Ratio Chi-Square = 1.253, DF = 2, P-Value = 0.534 square output for the ble of e-cigarettes and * NOTE * 1 cells with expected counts less than 5 essation.
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