22.5 cm? 8. If the bowling ball in problem 7 is accelerated at a rate of 2.1 rad/ applied to produce this acceleration?

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Chapter1: Units, Trigonometry. And Vectors
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8,7
8-5
7. What is the moment of inertia of a bowling ball that has a weight of 7.3 kg and a diameter of
22.5 cm?
8. If the bowling ball in problem 7 is accelerated at a rate of 2.1 rad/s², then how much torque was
applied to produce this acceleration?
Transcribed Image Text:8-5 7. What is the moment of inertia of a bowling ball that has a weight of 7.3 kg and a diameter of 22.5 cm? 8. If the bowling ball in problem 7 is accelerated at a rate of 2.1 rad/s², then how much torque was applied to produce this acceleration?
Expert Solution
Step 1: Given and Required

Mass of the bowling ball,

                     m space equals space 7.3 space k g

Diameter of the bowling ball,

                     d space equals space 22.5 space c m

Then radius will be,

                     r space equals space d over 2

r space equals space fraction numerator 22.5 space c m over denominator 2 end fraction

r space equals space 11.25 space c m space

r space equals space 0.1125 space m

Angular acceleration of the bowling ball,

                    alpha space equals space 2.1 space r a d divided by s squared

We need to find,

a) Moment of Inertia of bowling ball.

b) Torque on bowling ball.

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