7. If 200 joules of energy were used in 0.1 second, how many kilowatts of power were used? Physics-Problem Solving Entries Key Idea Finding out how much power is used. Stock of Data Solution Sanity Check 200 J/ 0.1s =2000 watts 8. A spring with a spring constant of 2.0 N/m is compressed by 50 cm. How much work was done on the spring? Physics-Problem Solving Entries Key Idea Stock of Data Solution Sanity Check

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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7. If 200 joules of energy were used in 0.1 second, how many kilowatts of power were used?
Physics-Problem Solving Entries
Key Idea
Finding out how much power is used.
Stock of Data
Solution
Sanity Check 200 J/ 0.1s = 2000 watts
8. A spring with a spring constant of 2.0 N/m is compressed by 50 cm. How much work was
done on the spring?
Physics-Problem Solving Entries
Key Idea
Stock of Data
Solution
Sanity Check
Transcribed Image Text:Last saved by user - Compatibility Mode Last Modified: Fri at 4:56 PM - P Search (Alt+Q) ut References Mailings Review View Help 7. If 200 joules of energy were used in 0.1 second, how many kilowatts of power were used? Physics-Problem Solving Entries Key Idea Finding out how much power is used. Stock of Data Solution Sanity Check 200 J/ 0.1s = 2000 watts 8. A spring with a spring constant of 2.0 N/m is compressed by 50 cm. How much work was done on the spring? Physics-Problem Solving Entries Key Idea Stock of Data Solution Sanity Check
ast saved by user Compatibility Mode Last Modified: Fri at 4:56 PM -
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References
Mailings
Review
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9. Calculate the work (in joules) done if 200 watts are used for 5 seconds.
Physics-Problem Solving Entries
Key Idea
Finding out how much work is done.
Stock of Data T= 5s, P= 200 watts
Solution P*T= J; 200 watts *5s= J
Sanity Check 200 watts *5s=1,000 J
Transcribed Image Text:ast saved by user Compatibility Mode Last Modified: Fri at 4:56 PM - P Search (Alt+Q) References Mailings Review View Help 9. Calculate the work (in joules) done if 200 watts are used for 5 seconds. Physics-Problem Solving Entries Key Idea Finding out how much work is done. Stock of Data T= 5s, P= 200 watts Solution P*T= J; 200 watts *5s= J Sanity Check 200 watts *5s=1,000 J
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