22. Although the standard molar entropy, (AS), of a lot of chemicals are available, (AS) of most chemicals, especially the newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar entropy of a few compounds. The following reaction occurs when sucrose (cane sugar) is metabolized by the body. 0 C12H22O11(s) + 12 O₂(g) → 12 CO₂(g) + 11 H₂O(1) ASn = 512.01 J/K What is the standard molar entropy, sº of sucrose solid? Substance sº mol K Substance so (mol K CO(g) 197.9 CO₂(g) 213.6 H₂O(g) 188.83 MgO(s) 69.91 26.8 0₂(8) H₂O(1) Mg(OH)2 (s) C(graphite, s) 63.24 205.0 5.69 J mol K N₂(g) 191.50
22. Although the standard molar entropy, (AS), of a lot of chemicals are available, (AS) of most chemicals, especially the newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar entropy of a few compounds. The following reaction occurs when sucrose (cane sugar) is metabolized by the body. 0 C12H22O11(s) + 12 O₂(g) → 12 CO₂(g) + 11 H₂O(1) ASn = 512.01 J/K What is the standard molar entropy, sº of sucrose solid? Substance sº mol K Substance so (mol K CO(g) 197.9 CO₂(g) 213.6 H₂O(g) 188.83 MgO(s) 69.91 26.8 0₂(8) H₂O(1) Mg(OH)2 (s) C(graphite, s) 63.24 205.0 5.69 J mol K N₂(g) 191.50
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![22.
Although the standard molar entropy, (AS), of a lot of chemicals are available, (AS) of most chemicals, especially the
newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar
entropy of a few compounds.
The following reaction occurs when sucrose (cane sugar) is metabolized by the body.
0
C12H22O11(s) + 12 O₂(g) → 12 CO₂(g) + 11 H₂O(1) ASrxn = 512.01 J/K
What is the standard molar entropy, 50 of sucrose solid?
Substance
So
J
mol K
Substance
sº
G
(molk)
CO(g)
197.9
CO₂(g)
213.6
H₂O(g) MgO(s)
188.83
26.8
69.91
0₂(g)
H₂O(1) Mg(OH)2 (s) C(graphite, s)
63.24
205.0
5.69
J
mol K
N₂(g)
191.50](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90a13131-8e27-405e-a576-af0f707ba66e%2Ffb5cb2a6-e15a-461b-ad0f-4c8d8a83aa32%2Fbbiumdb_processed.png&w=3840&q=75)
Transcribed Image Text:22.
Although the standard molar entropy, (AS), of a lot of chemicals are available, (AS) of most chemicals, especially the
newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar
entropy of a few compounds.
The following reaction occurs when sucrose (cane sugar) is metabolized by the body.
0
C12H22O11(s) + 12 O₂(g) → 12 CO₂(g) + 11 H₂O(1) ASrxn = 512.01 J/K
What is the standard molar entropy, 50 of sucrose solid?
Substance
So
J
mol K
Substance
sº
G
(molk)
CO(g)
197.9
CO₂(g)
213.6
H₂O(g) MgO(s)
188.83
26.8
69.91
0₂(g)
H₂O(1) Mg(OH)2 (s) C(graphite, s)
63.24
205.0
5.69
J
mol K
N₂(g)
191.50
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