20. Although the standard molar entropy, (AS"), of a lot of chemicals are available, (AS) of most chemicals, especially the newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar entropy of a few compounds. Trinitrotoluene (C₂H5N3O6), abbreviated as TNT is one of the most famous explosives. Please use the above table and the standard entropy of reaction of the detonation reaction of TNT to find the Sº of TNT. 0 2 C₂H5N306(s) → 3 N₂(g) + 5 H₂O(g) + 7 CO(g) + 7 C(graphite,s) ASn = 488.9 J/K so of TNT = Substance sº mol K Substance Sº (mlk) mol K CO(g) 197.9 CO₂(g) 213.6 H₂O(g) 188.83 MgO(s) O₂(g) 69.91 26.8 H₂O(1) Mg(OH)₂ (s) C(graphite, s) 205.0 63.24 5.69 N₂(g) 191.50

20. Although the standard molar entropy, (AS"), of a lot of chemicals are available, (AS) of most chemicals, especially the newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar entropy of a few compounds. Trinitrotoluene (C₂H5N3O6), abbreviated as TNT is one of the most famous explosives. Please use the above table and the standard entropy of reaction of the detonation reaction of TNT to find the Sº of TNT. 0 2 C₂H5N306(s) → 3 N₂(g) + 5 H₂O(g) + 7 CO(g) + 7 C(graphite,s) ASn = 488.9 J/K so of TNT = Substance sº mol K Substance Sº (mlk) mol K CO(g) 197.9 CO₂(g) 213.6 H₂O(g) 188.83 MgO(s) O₂(g) 69.91 26.8 H₂O(1) Mg(OH)₂ (s) C(graphite, s) 205.0 63.24 5.69 N₂(g) 191.50

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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22. Although the standard molar entropy, (AS), of a lot of chemicals are available, (AS) of most chemicals, especially the newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar entropy of a few compounds. The following reaction occurs when sucrose (cane sugar) is metabolized by the body. 0 C12H22O11(s) + 12 O₂(g) → 12 CO₂(g) + 11 H₂O(1) ASrxn = 512.01 J/K What is the standard molar entropy, 50 of sucrose solid? Substance So J mol K Substance sº G (molk) CO(g) 197.9 CO₂(g) 213.6 H₂O(g) MgO(s) 188.83 26.8 69.91 0₂(g) H₂O(1) Mg(OH)2 (s) C(graphite, s) 63.24 205.0 5.69 J mol K N₂(g) 191.50