For each system listed in the first column of the table below, decide (ifpossible) whether the change described in the second column willincrease the entropy s of the system, decrease s, or leave s unchanged.If you don't have enough information to decide, check the "not enoughinformation" button in the last column.oloSystemChangeAsArO As < 0The nitrogen is heated from 7.0 °C to38.0 °C and also expands from avolume of 3.0 L to a volume ofO As = 0A few moles of nitrogen (N2) gas.O As > 015.0 L.not enoughinformationO As < 0The carbon dioxide is compressedO As = 0from a volume of 12.0 L to a volumeA few moles of carbon dioxide (CO2) gas.of 5.0 L while the temperature is heldO As > 0constant at -15.0 °C.not enoughinformationO AS< 0AS = 0The water is heated from -9.0 °C toA few grams of liquid water (H,0).54.0 °C.O AS> 0not enoughinformationO O

Entropy is basically the measure of randomness. In solids constituent particles are well arranged…

For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy s of the system, decrease s, or leave s unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. 圖 System Change AS O AS <0 The nitrogen is heated from 7.0 °C to 38.0 °C and also expands from a O AS = 0 A few moles of nitrogen (N2) gas. volume of 3.0L to a volume of 15.0 L. O As> 0 not enough information O As<0 The carbon dioxide is compressed O AS = 0 from a volume of 12.0 L to a volume A few moles of carbon dioxide (CO,) gas. of 5.0 L while the temperature is held O AS>0 constant at -15.0 °C. not enough information O AS< 0 O AS = 0 The water is heated from -9.0 °C to A few grams of liquid water (H,0). 54.0 °C. O AS > 0 not enough information

For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy s of the system, decrease s, or leave s unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. 圖 System Change AS O AS <0 The nitrogen is heated from 7.0 °C to 38.0 °C and also expands from a O AS = 0 A few moles of nitrogen (N2) gas. volume of 3.0L to a volume of 15.0 L. O As> 0 not enough information O As<0 The carbon dioxide is compressed O AS = 0 from a volume of 12.0 L to a volume A few moles of carbon dioxide (CO,) gas. of 5.0 L while the temperature is held O AS>0 constant at -15.0 °C. not enough information O AS< 0 O AS = 0 The water is heated from -9.0 °C to A few grams of liquid water (H,0). 54.0 °C. O AS > 0 not enough information

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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eq M M IS M ots M M M # 3 E D Consider the reaction 2H₂O(l) 2H₂(g) + O₂(g) The standard free energy change for this reaction is 474.2 kJ. The free energy change when 1.88 moles of H₂O(1) react at standard condition is kJ. 20 C What is the maximum amount of useful work that the reaction of 1.88 moles of H₂O(l) is capable of producing in the surroundings under standard conditions? If no work can be done, enter none. kJ Submit Answer $ 4 R F > % 5 T [References] Use the References to access important values if needed for this question. Retry Entire Group 9 more group attempts remaining G Cengage Learning Cengage Technical Support 6 B MacBook Pro Y Topics] H & 7 N U J ▶II * 00 8 M I ( 9 K. O < 96 ) L P V t Previous Email Instructor Save and Exit { + 11 [ Next ? } 1 dele
1:44 1 LTE 4 1 Search Question 20.b of 23 Show Answer Consider the reaction Cl2(g) + Br2(g) → 2 BrCI(g) at 25 °C. Which of the following best explains why the change in entropy is so small? A) All of the components in the chemical equation are gases. B) There are the same moles of gas on both sides of the reaction. C) The temperature of the reaction does not change. Tap here or pull up for additional resources
What is the change in entropy, AS, for the following reaction? Use Table G in your book for values of standard entropies. Your answer should be in J/K mol. CaCO3(s) + 2 H'(aq) → → Ca² (aq) + H₂O(l) + CO2(g) O 264.9 J/K mol O 118.6 J/K mol 394.3 J/K mol 137.7 J/K mol 2
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3. What change will increase the entropy of the system? Group of answer choices liquid to solid solid to gas gas to liquid gas to solid 2.ΔSsyst>0 for the following reaction: Group of answer choices A, 2NO (g) + O2(g) → 2NO2(g) B, HCl (g) + NH3(g) → NH4Cl (s) C, C3H8(g) + 5 O2(g) → 3CO2 (g) + 4 H2O (g) D, 2N2 (g) + 3H2(g) → 2NH3(g) E, Pb2+(aq) + 2Cl-(aq) → PbCl2 (s)
For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S, or leave S unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column. System Change AS O AS 0 not enough information O AS 0 not enough O information O AS 0 not enough O information Explanation Check O 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center | O O
Which one of the systems would have more entropy and why if there's 3 particles w a total energy of 12 J
For a particular reaction at 148.1 °C, delta G=−1428.51 kJ, and delta S =393.69 J/K . Calculate delta G for this reaction at −62.8 °C. Free energy is related to enthalpy, temperature, and entropy through the equation delta G = delta H -T(delta S) Δ?=Δ?−?Δ? delta H = delta G + T (delta S) Solve for the enthalpy of the reaction. Assume that enthalpy and entropy will not change between the two temperatures. Use the values from the prior scenario (temperature) to determine the new free energy value using the first equation.
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