22. A pointer variable whose sole purpose is to locate the first node in a linked list is calledb. the node's linka. the list's topc. the list's linkd. the list's head

A linked list is a list of data elements linked in a sequence. It consists of nodes where each node…

Answered: 22. A pointer variable whose sole…

22. A pointer variable whose sole purpose is to locate the first node in a linked list is called a. the list's top b. the node's link c. the list's link d. the list's head

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

QUESTION 4 in phython language Write a program that creates a list of N elements (Hint: use append() function), swaps the first and the last element and prints the list on the screen. N should be a dynamic number entered by the user. Sample output: How many numbers would you like to enter?: 5 Enter a number: 34 Enter a number: 67 Enter a number: 23 Enter a number: 90 Enter a number: 12 The list is: [12, 67,23, 90, 34]
A)Draw the linked node structure created by the following program and , B)List the output of program. struct node{ struct node *left; char letter; struct node *right; }; typedef struct node *NODEPTR; NODEPTR getnode(void); void displayList(NODEPTR); void main() { NODEPTR p , list , save; char one; p=getnode(); p->letter='A'; list=p; p->right=p; p->left=p; save=list; for(int i=2;i<8;i+=2) { one='A'+ i; p=getnode(); p->letter=one; p->left=save; save->right=p; save=p; printf("Letter= %c\n",p->letter); } list->left=save; save->right=list; list=p; displayList(list); } void displayList(NODEPTR head) {NODEPTR save; printf("\nLIST\n"); save=head; do {printf("%c ",save->letter); save=save->left; }while(save!=head); } NODEPTR getnode() { NODEPTR q; q = (NODEPTR) malloc(sizeof(struct node));…
The mapped list pattern Our second pattern is the mapped list pattern, described in video 4 3 mapped list pattern. Often we need to write a function that takes a list as a parameter and returns a new list in which each item in the original list is "mapped" to a new item in the result list. For example, the following function takes a list of numbers as a parameter and returns a list of all the numbers squared, e.g. squares ( [1, 3, 7]) returns [1, 9, 49]. def squares (nums): "Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result Although this is just a special case of the accumulator pattern, it is so common that we give it its own name: the mapped list pattern. Consider the following function: def squares(nums): ""Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result If the main program calls print(squares ( [5, -3, 2, 7]) what is the state table for the function…
struct nodeType { int infoData; nodeType * next; }; nodeType *first; … and containing the values(see image) Using a loop to reach the end of the list, write a code segment that deletes all the nodes in the list. Ensure the code performs all memory ‘cleanup’ functions.
11111 2) Name: 2. The following procedure is intended to return the number of times the value val appears in the list myList. The procedure does not work as intended. Line 01: PROCEDURE countNumOccurences (myList, val) Line 02: { Line 03: FOR EACH item IN myList Line 04: } BL Line 05: count 0 Line 06: IF(item = val) %3D Line 07: Line 08: count count + 1 :60 Line 10: { { RETURN(count) Line 11: Line 12: } Which of the following changes can be made so that the procedure will work as intended? a. Moving the statement in line 5 so that it appears between lines 2 and 3 C. Changing line 6 to IF(item = count) b. Changing line 6 to IF(myList[item] = val) d. Moving the statement in line 11 so that it appears between lines 9 and 10
write the following program using simply linked list in C++ language Add definition of the following functions into a simply linked list: 1) Insert before tail : Insert a value into a simply linked list, such that it's location will be before tail. So if a list contains {1, 2, 3}, insert before tail value 9 is called, the list will become {1, 2, 9, 3}. 2) Insert before value : Insert a value into a simply linked list, such that it's location will be before a particular value. So if a list contains {1, 2, 3}, insert before 2 value 9 is called, the list will become {1, 9, 2, 3}. 3)Count common elements : Count common values between two simply linked lists. So if a list1 contains {1, 2, 3, 4, 5}, and list2 contains {1, 3, 4, 6}, number of common elements is 3. 4) Check if sorted : Check if elements of simply linked lists are sorted in ascending order or not. So if a list contains {1, 3, 7, 8, 9} its sorted, but if a list contains {1, 3, 7, 2, 5} its not sorted. 5) Find…
code in c program
2-) In a double linked list, the structure of a node is defined as follows: struct node { int employeeNo; char name[20]; struct node *next; structnode *prev; }node; the nodes in the list are sorted according to employeeNo in ascending order (from smaller to larger ). Write a function to insert a node with a given name and employeeNo into the list so that the list will remain the sorted. employeeNo değerine göre kiüçükten büyüğe sıralanmış bir çift bağlı liste olsun. Verilen bir isim ve employeeNo değerine sahip düğümü listeye sıra bozulmayacak şekilde ekleyen bir fonksyion yazınız.
programming language: C
This term refers to an individual item in a list.a. elementb. binc. cubbyholed. slot
# This function takes a list of points and returns a new list of points, # beginning with the first point and then at each stage, moving to the closest point that has not yet been visited.# Note: the function should return a new list, not modify the existing list.# Hint: use a while loop to repeat while the list of remaining points is not empty
Write a function ListNode *ListConcat(ListNode *list1, ListNode *list2) That concatenates the items in list2 to the end of list1 and returns the resulting list.