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2=1d. I'd. a. If 0.111 moles of pentane (CsH12) is mixed with 0.313 moles of oxygen (O₂), which is the limiting reactant? 10 - (Bag (0₂) 6

2=1d. I'd. a. If 0.111 moles of pentane (CsH12) is mixed with 0.313 moles of oxygen (O₂), which is the limiting reactant? 10 - (Bag (0₂) 6

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2a & 2B

b. What is the theoretical yield (in grams) of carbon dioxide and water for this reaction? THERE hmoty 159 (3) 8. 1946 12 toeg Hydrogen reacts with nitrogen to form ammonia by the following equation: mol.) 3 H₂(g) + N₂(g) → 2 NH³(g) R a. What is the limiting reactant if 1.60 g of hydrogen are mixed with 6.90 g of nitrogen? NITROGEN IS THE LIMITED REACTANT. MORE AMMONIA CAN BE PRODUCED FROM HYDROGEN TUAN NITROGEN. b. What is the theoretical yield of ammonia (in grams)? (NH = 17,03/9/mol 2.02 g/mol = 28ğimal 1.60 g (H₂) (H₂) mol 2.02 9. •79mol (H₂) •79mal (H₂)/2 mo (NH3) 3mol(H₂)
Transcribed Image Text:b. What is the theoretical yield (in grams) of carbon dioxide and water for this reaction? THERE hmoty 159 (3) 8. 1946 12 toeg Hydrogen reacts with nitrogen to form ammonia by the following equation: mol.) 3 H₂(g) + N₂(g) → 2 NH³(g) R a. What is the limiting reactant if 1.60 g of hydrogen are mixed with 6.90 g of nitrogen? NITROGEN IS THE LIMITED REACTANT. MORE AMMONIA CAN BE PRODUCED FROM HYDROGEN TUAN NITROGEN. b. What is the theoretical yield of ammonia (in grams)? (NH = 17,03/9/mol 2.02 g/mol = 28ğimal 1.60 g (H₂) (H₂) mol 2.02 9. •79mol (H₂) •79mal (H₂)/2 mo (NH3) 3mol(H₂)
How many grams of Cr metal would be needed to produce 38.2 g of chromium (III) oxide? OXIDE -2 Cr+3 4cr +30272cr₂03 =-251mol (cr203) .123mol (cr) • 123mo (Cr) (S 52 9=6.4 mol (Cr 2. Pentane combusts with oxygen to form carbon dioxide and water by the following reaction: C. 38.2 g (cr₂03)/ 1 Mal 152 9 MOLES OF or astmul(cr₂03) 2 MOI (cr) Limiting Reactant, Theoretical Yield and Percent Yield 2=12.12 5=60.05 >12.17g/mo a. If 0.111 moles of pentane (C5H12) is mixed with 0.313 moles of oxygen (O₂), which is the limiting reactant? 13 C5H12(l) + 8 O2(g) → 5 CO2(g) + 6 H₂O(g) (0 X my reage (329 (0₂) 6
Transcribed Image Text:How many grams of Cr metal would be needed to produce 38.2 g of chromium (III) oxide? OXIDE -2 Cr+3 4cr +30272cr₂03 =-251mol (cr203) .123mol (cr) • 123mo (Cr) (S 52 9=6.4 mol (Cr 2. Pentane combusts with oxygen to form carbon dioxide and water by the following reaction: C. 38.2 g (cr₂03)/ 1 Mal 152 9 MOLES OF or astmul(cr₂03) 2 MOI (cr) Limiting Reactant, Theoretical Yield and Percent Yield 2=12.12 5=60.05 >12.17g/mo a. If 0.111 moles of pentane (C5H12) is mixed with 0.313 moles of oxygen (O₂), which is the limiting reactant? 13 C5H12(l) + 8 O2(g) → 5 CO2(g) + 6 H₂O(g) (0 X my reage (329 (0₂) 6
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