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(20+j12)= ( 10- j6)=(4+J5)#(2+j3) = Z. (45-J co) - ( 30 +j 10) =(5+ ja) = 5, (120+ J 100) + (1110+ 180) 4. (9+j15) + ( 10-8)=(30+)12) = ai +sl 21f =1)

(20+j12)= ( 10- j6)=(4+J5)#(2+j3) = Z. (45-J co) - ( 30 +j 10) =(5+ ja) = 5, (120+ J 100) + (1110+ 180) 4. (9+j15) + ( 10-8)=(30+)12) = ai +sl 21f =1)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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FIND THE ABSOLUTE VALUES

(20+j12)= ( 10- j6)=(4+J5)#(2+j3) = Z. (45-J co) - ( 30 +j 10) =(5+ ja) = 5, (120+ J 100) + (1110+ 180) 4. (9+j15) + ( 10-8)=(30+)12) = ai +sl 21f =1)
Transcribed Image Text:(20+j12)= ( 10- j6)=(4+J5)#(2+j3) = Z. (45-J co) - ( 30 +j 10) =(5+ ja) = 5, (120+ J 100) + (1110+ 180) 4. (9+j15) + ( 10-8)=(30+)12) = ai +sl 21f =1)
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