2018 lan รอเจอ apply KVL in Mesh (16 +35) 1 - 51 - 200 forom Mesh and I-T=4/0° 1 + 1 = 1 /0 I+I 5 + (35 ) 1 + 1 51 + 1 + 1 = 0 Salve egn, and 3 H H I 1. 49 -70-16 A = 2.9 /162.57° A = 2.1 /34.45° A = 0 0 (3) 0

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using the thevenin equation from terminal a-b. at the solve eqn 1, 2 and 3 how did they get the values of I1, I2 and I3. pls show the equation.

Calculation of Vin
-j4
lan
เรือเจริ
14L0
js
2010
then,
apply KVL in Mesh 1
from Mesh and Ⓒ
I₁₂-1₂₁
= 4200
-Ţ₂² + I₂ = 4 10²
(lo+j5) ₁-j5 1₂ = 20/0°
Salve eqn, and Ⓡ
-jsI+ (j5-j4) I₂ + 4 I ₂ = 0
-j5I +j1₂ + 4√3 = 0·
H
= 1.49 /-70.48° A
Į₂
= 2.4 /162.57° A
गु 2.4 /37.45° A
Vth
Vth
=
www
4I3
42
9.637-43° V
-0
Transcribed Image Text:Calculation of Vin -j4 lan เรือเจริ 14L0 js 2010 then, apply KVL in Mesh 1 from Mesh and Ⓒ I₁₂-1₂₁ = 4200 -Ţ₂² + I₂ = 4 10² (lo+j5) ₁-j5 1₂ = 20/0° Salve eqn, and Ⓡ -jsI+ (j5-j4) I₂ + 4 I ₂ = 0 -j5I +j1₂ + 4√3 = 0· H = 1.49 /-70.48° A Į₂ = 2.4 /162.57° A गु 2.4 /37.45° A Vth Vth = www 4I3 42 9.637-43° V -0
20Lov
Given Circuit
lan
mw
lan
www
-j4
according to question, we need to find
Thevenin equivalent from terminal a-b.
Calculation of th
j5
-j42
HH
jsn (1)42A
Zth
www
= 1.33
€422
Zth = [(10 || js)-j4
www
"4]||"
45
a
Zth
Transcribed Image Text:20Lov Given Circuit lan mw lan www -j4 according to question, we need to find Thevenin equivalent from terminal a-b. Calculation of th j5 -j42 HH jsn (1)42A Zth www = 1.33 €422 Zth = [(10 || js)-j4 www "4]||" 45 a Zth
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