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2+0.1=- 1+=1 In the figure shown below, the ZT of x(n) is X(=) = --| = /> 1, and 1 H(z) 1-0.97-1 » [Z]>0.9. Then, the system output y(n) is given by x(п) y(n) H(z) A. y(n) = (-1)" u(1) + (0.9)"«(n) 5 (-1)" u(n %3D C. y() = u(1) +(0.9)*u(m) D. y(n) =(-1)"u(1) –(0.9)"#(») 5 O A. . O B. . O . O D. .

2+0.1=- 1+=1 In the figure shown below, the ZT of x(n) is X(=) = --| = /> 1, and 1 H(z) 1-0.97-1 » [Z]>0.9. Then, the system output y(n) is given by x(п) y(n) H(z) A. y(n) = (-1)" u(1) + (0.9)"«(n) 5 (-1)" u(n %3D C. y() = u(1) +(0.9)*u(m) D. y(n) =(-1)"u(1) –(0.9)"#(») 5 O A. . O B. . O . O D. .

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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2+0.1=- 1+=1 In the figure shown below, the ZT of x(n) is X(=) = --| = /> 1, and 1 H(z) 1-0.97-1 » [Z]>0.9. Then, the system output y(n) is given by x(п) y(n) H(z) A. y(n) = (-1)" u(1) + (0.9)"«(n) 5 (-1)" u(n %3D C. y() = u(1) +(0.9)*u(m) D. y(n) =(-1)"u(1) –(0.9)"#(») 5 O A. . O B. . O . O D. .
Transcribed Image Text:2+0.1=- 1+=1 In the figure shown below, the ZT of x(n) is X(=) = --| = /> 1, and 1 H(z) 1-0.97-1 » [Z]>0.9. Then, the system output y(n) is given by x(п) y(n) H(z) A. y(n) = (-1)" u(1) + (0.9)"«(n) 5 (-1)" u(n %3D C. y() = u(1) +(0.9)*u(m) D. y(n) =(-1)"u(1) –(0.9)"#(») 5 O A. . O B. . O . O D. .
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