2.Water exits a reservoir through a 1-Km long D=?mm diameter horizontal Tunnel as shown below. The entrance is sharp-edged, and the discharge is to the lower reservoir. If the flow rate is 2 CMS, What tunnel diameter is required to achieve the desired flow rate if local losses are neglected? Upper reservoir Tunnel = 1 km 23 m Lower reservoir

Q: 1. The three reservoirs shown below are connected by commercial steel pipe (e=0.045mm.). Determine…

A: Reservoir : When a dam is built across a river, water is held on the upstream side of the dam,…

Q: Note:hand written solution should be avoided.

A: Approach to solving the question: Detailed explanation:Examples: Key references:

Q: 4.1.11. The surface elevation difference between two reservoirs, 25 km apart, is 80 m. Ductile iron…

A:

Q: Water flows over a smooth submerged object in a channel of width 1.2 m. The water depth upstream of…

A:

Q: For the two-dimensional flow system shown below (units in meters):Compute the total flow rate under…

A: From the flow net, the number of flow channels is 3 and the number drops is 10. Given, x = 4; y = 8

Q: Q1) In a rectangular channel with a base width of 3 m, the depth of the water is 0.5 m and the flow…

A: The channel is rectangularWidth of base, B = 3 mDepth of water, y1 = 0.5 mVelocity of flow, V1 = 5…

Q: Two pipes are connected in parallel between two reservoirs: L1= 2000 m, D1= 160 cm, C1=120; L2= 1400…

A: Given: Two pipes connected in parallel,L1 = 2000 m     L2 = 1400 mD1 = 160 cm    D2 = 800 mmC1 = 120…

Q: 8.63 Two reservoir maintain a constant difference of water levels of 11.25 m and are connected by a…

A: Given data, Here the value of V ( flow velocity through pipe ) is unknown. To find the value of V…

Q: 10.67 In a rectangular channel 4 m wide flow of 7.65 m/s the depth is 0.4 m. If a hydraulic jump is…

A: We have equation2q2g=y1y2y1+y2

Q: A trapezoidal channel is to be designed for the maximum efficiency to carry a discharge of 10m2/s.…

A: The maximum efficiency of the channel is achieved by calculating the dimension for the hydraulically…

Q: wo reservoirs having difference in water levels as 12m are connected by a pipe line 3 km long and 30…

A:

Q: A hydraulic jump is situated a 4 m wide rectangular channel. The discharge in the channel is 7.5…

A:

Q: A rectangular channel is 4 m wide, and it reduces to 2 m through a hydraulic structure. Assuring the…

A: The specific energy at the constriction is given as 6 m. Assuming choking occurs, we can use the…

Q: A trapezoidal channel has a bottom width of 6 m and side slope of 1:1. The depth of flow is 2 m at a…

A:

Q: Water is moving between two reservoirs at a flow rate of 0.08 m³/s via the pipes shown in the…

A: Given: D1=10cm, D2=20cm, Ks=0.08, Flow rate=0.08m3/s , L1=50m

Q: Reservoir I WSI Figure P4.3.2 Reservoir 3 Pipe 1 WS2 = 1,580 m WS3 = 1,550 m WS3 VH₁ J Pipe 3 Pipe 2…

A:

Field applications of hydraulic conductivity

Hydraulic conductivity is one of the hydraulic properties of soil defined as a measurement of the ability of a porous medium to permit water movement or fluid flow through it. It is denoted by the letter K. It is influenced by the density and viscosity of the fluid. It is also called permeability. Hydraulic conductivity is defined as the ratio of velocity to the hydraulic gradient. The different methods used to determine the hydraulic conductivity are laboratory methods (constant head permeability tests and falling head tests), in-situ field methods (pumping in and pumping out tests), small scale field tests (infiltration tests and slug tests), and indirect methods such as estimation from grain size, consolidation test data, and horizontal capillary test. The pedotransfer function (PTF) method is a specific empirical estimating approach employed in the soil sciences is also used to determine the hydraulic conductivity of the soil.