2.The velocity components of a particle with a charge of -3.6µC vx = 7.5 × 10 6m/s and vy = -4.9 x 10 It is given as 6m/s. As the particle passes exactly through the origin, x = 0.3 m, Calculate the magnetic field vector formed at y = 0.4 m and z = 0 Note: ɛ0 = 8.85 x 10^-12 C^2/Nm^2 ve u0 = 47T x 10^-7 Tm/A %3D %3D

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Chapter1: Units, Trigonometry. And Vectors
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2.The velocity components of a particle with a
charge of -3.6µC vx = 7.5 × 10 6m/s and vy =
-4.9 x 10 It is given as 6m/s. As the particle
passes exactly through the origin, x = 0.3 m,
Calculate the magnetic field vector formed at y
= 0.4 m and z = 0
%3D
Note: €0 = 8.85 × 10^-12 C^2/Nm^2 ve µ0 = 47T
x 10^-7 Tm/A
%3D
Transcribed Image Text:2.The velocity components of a particle with a charge of -3.6µC vx = 7.5 × 10 6m/s and vy = -4.9 x 10 It is given as 6m/s. As the particle passes exactly through the origin, x = 0.3 m, Calculate the magnetic field vector formed at y = 0.4 m and z = 0 %3D Note: €0 = 8.85 × 10^-12 C^2/Nm^2 ve µ0 = 47T x 10^-7 Tm/A %3D
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