cm74973551..65x7465189*6.71-38lsbeen 159.68 cm+447495.1*2.5 (9)TEIC. P(Z < 2.13)$0.0 (9)and 178.7 cmd. P(-0.45 < z < 2.29)J4=1447 XSeight of 15 to 18-old males from Chile2= X-Me. Find c if P(Z > c) = 0.39.30.0 (b)PEA.88 (b)521f. Find c if P(-c 1.24) 29tunima.II (b)Page 1 of 4SX2X=4+2(0)SmolברךVNIHO NI LName:zwod 3E.IS equor 8 (5)88.0 (p)Found97.35 % ofmal Distribution (Conce8\x (d)AXXI (d)81.0 (d)*28.CA (5) AT bris OE (d)88.0 (0)11.0 (d)e2.0 (p)0 (d)A8 IV (9)tsszonow I asW169wo way noZ~ N CM Gnwo muoy no olwo way no onwo uby nonwo wuoy no o 98aro (6) Ta1.ea bns 48 23 (1)ماما ،.281.377. The golf scores for a school team were normally distributed with a mean of 68 and a standard deviation ofThen X~ N(6₂8three. Let X = golf score for a random school team, then fill in the blanks:31

we have to fill blanks. z follows standard normal distribution. here we note that area under…

Answered: 2.5 (9) Week 7 worksheet 6. For a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Pumpkins from a local farmer have a mean weight of 16 pounds with a standard deviation of 2.5 pounds. What is the z-score of an 21 pound pumpkin? z=-2 z=+2 z=-1 z=+1
Part C
You are the manager of a restaurant that delivers pizza to customers. You have just changed your delivery process in an effort to reduce the mean time between the order and completion of delivery from the current 25 minutes. From past experience, you can assume that the population standard deviation is 6 minutes. A sample of 36 orders using the new delivery process yields a sample mean of 22.29 minutes. Complete parts (a) to (d) below. Question content area bottom Part 1 a. Using the critical value approach, at the 0.05 level of significance, is there evidence that the mean delivery time has been reduced below the previous population mean value of 25 minutes? Let μ be the population mean. State the null hypothesis, H0, and the alternative hypothesis, H1. A. H0: μ≤25 H1: μ>25 B. H0: μ≥25 H1: μ<25 C. H0: μ≠25 H1: μ=25 D. H0: μ=25 H1: μ≠25 Part 2 The level of significance is 0.05 and the sample size…
Use the following frequency distribution table to find the value of the mean score. Scores Frequency 1-5 3 6-10 6 11-15 7 02.7 09.3 09.8 O 5.3 08.0 Submit Question DII R F F4 % 5 T G J F5 A 6 H F6 & 7 PrtScn 8 FB K Home 9 F9 O End ) 0 F10 ^C P
Im confused on #1.) Letter C. I already found the 68% range and the 95% range by using the empirical rule. Now it is asking " What percentage of this sample fall bellow 90? With the mean of 78 and standard deviation of 6.
a. What does 1 standard deviation mean? b. What percentage of scores are falling between the mean and 1 standard deviation?
Heights of boys in a high school are approximately normally distributed with a mean of 175 cm and a standard deviation of 5 cm. What is the first quartile (25%) of heights? (Hint. you need to find the Z-score associated with 25th percentile from the table on page 410) a. 165.8 cm b. 169.6 cm c. 171.7 cm d. 173.5 cm e. 181.0 cm
18
C ,d,e
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
A large chemistry course took their final exam. The mean was 75 with a standard deviation of 8. What are the exam scores that separate the top and bottom 5 percent of the class (extreme 10%) 2. What are the exams scores that separate the middle 10% of the class (5% on each side of the mean)? Use table below and draw normal distribution
(c) 3. A standard die is rolled 36 times. The results are shown in the following table. 4 5 6 3 Score 1 2 Frequency 3 (a) Write down the standard deviation. 1.63 Write down the median score. 4.5 Find the interquartile range. 5-3-2 (b) 5 4 6 10 52. 8

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2.5 (9) Week 7 worksheet 6. For a standard normal distribution (2), answer the following: zor DE.IS equor $8 a. Fill in the blanks. 04 b. P(Z > 1.24) 29tunima.II (b) (@c. P(Z < 2.13) C. 50.05 2=X-M WAB (b) a2.0 (b) PEA.38 (b) d. P(-0.45 c) = 0.39. X=4+2(0) smol f. Find c if P(-c