Using the site. A writer for the school newspaper tests this claim by choosing a random sample of 170 students who visited the site looking for a roommate. Of the students surveyed, 56 said they found a match their first time using the site. Foommates. According to the school's reports, 38% of students will Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that the proportion, p, of all students who will find a match their first time using the site is 38%. (a) State the null hypothesis Ho and the alternative hypothesis H, that you would use for the test. Ho: D 0 Р ô OO H₁: 0 E 020 0=0 *O X 5 ? (b) For your hypothesis test, you will use a Z-test. Find the values of np and n (1-p) to confirm that a Z-test can be used. (One standard is that np≥10 and n (1-p)≥10 under the assumption that the null hypothesis is true.) Heren is the sample size and p is the population proportion you are testing. np=0 n (1-p)= (c) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test.

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**Hypothesis Testing for Proportions**

When conducting research, one often needs to perform hypothesis testing to draw conclusions about data. This exercise will guide you through the steps of conducting a hypothesis test to check whether there is enough evidence to reject the claim about a proportion of students finding a match using a roommate site.

**Step-by-Step Guide:**

1. **Setting Hypotheses:**
   - **Classify Null Hypothesis \( H_0 \)** and **Alternative Hypothesis \( H_1 \)**
     \[
     H_0: \quad \text{p = 0.38}
     \]
     \[
     H_1: \quad \text{p > 0.38}
     \]

2. **Confirming Z-test Conditions:**
   - Calculate \( np \) and \( n(1 - p) \) under the assumption that the null hypothesis is true. Here, \( n \) is the sample size and \( p \) is the population proportion you are testing.
     \[
     np = 170 \times 0.38 = 64.6
     \]
     \[
     n(1 - p) = 170 \times (1 - 0.38) = 105.4
     \]
     Both \( np \) and \( n(1 - p) \) must be greater than or equal to 10 for the Z-test to be valid.

3. **Performing the Z-test:**
   - Calculate the test statistic which is given by:
     \[
     Z = \frac{\hat{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}
     \]
     Where \(\hat{p}\) is the sample proportion.

4. **Finding the p-value:**
   - The p-value represents the probability of obtaining test results at least as extreme as the results actually observed, under the assumption that the null hypothesis is correct. 
   - Typically, the p-value is derived from a standard normal distribution graph and is two times the area under the curve to the left of the Z value.

   **Graphs and Diagrams Explanation:**

   - There is a visual representation to help select one-tailed or two-tailed tests, and decide whether the critical area lies in one or two tails of the normal distribution.
   - The bell-shaped curve shown represents a standard normal distribution S
Transcribed Image Text:**Hypothesis Testing for Proportions** When conducting research, one often needs to perform hypothesis testing to draw conclusions about data. This exercise will guide you through the steps of conducting a hypothesis test to check whether there is enough evidence to reject the claim about a proportion of students finding a match using a roommate site. **Step-by-Step Guide:** 1. **Setting Hypotheses:** - **Classify Null Hypothesis \( H_0 \)** and **Alternative Hypothesis \( H_1 \)** \[ H_0: \quad \text{p = 0.38} \] \[ H_1: \quad \text{p > 0.38} \] 2. **Confirming Z-test Conditions:** - Calculate \( np \) and \( n(1 - p) \) under the assumption that the null hypothesis is true. Here, \( n \) is the sample size and \( p \) is the population proportion you are testing. \[ np = 170 \times 0.38 = 64.6 \] \[ n(1 - p) = 170 \times (1 - 0.38) = 105.4 \] Both \( np \) and \( n(1 - p) \) must be greater than or equal to 10 for the Z-test to be valid. 3. **Performing the Z-test:** - Calculate the test statistic which is given by: \[ Z = \frac{\hat{p} - p}{\sqrt{\frac{p(1 - p)}{n}}} \] Where \(\hat{p}\) is the sample proportion. 4. **Finding the p-value:** - The p-value represents the probability of obtaining test results at least as extreme as the results actually observed, under the assumption that the null hypothesis is correct. - Typically, the p-value is derived from a standard normal distribution graph and is two times the area under the curve to the left of the Z value. **Graphs and Diagrams Explanation:** - There is a visual representation to help select one-tailed or two-tailed tests, and decide whether the critical area lies in one or two tails of the normal distribution. - The bell-shaped curve shown represents a standard normal distribution S
### Understanding Standard Normal Distribution for Hypothesis Testing

#### Step-by-Step Guide:

**Step 1: Select one-tailed or two-tailed.**
- Options:
  - One-tailed
  - Two-tailed
  
**Step 2: Enter the test statistic. (Round to 3 decimal places.)**

**Step 3: Shade the area represented by the *p*-value.**
- This involves indicating the region under the normal curve that corresponds to the *p*-value.

**Step 4: Enter the *p*-value. (Round to 3 decimal places.)**

#### Example

A chart illustrating a Standard Normal Distribution is provided. The curve peaks at the mean (0) and has symmetrical tails extending to -3 and 3. The height of the curve represents the probability density.

#### Interpretation Based on the *p*-value:

**(d) Based on your answer to part (c), choose what can be concluded, at the 0.10 level of significance, about the claim made in the school’s reports:**

1. **Option A:**
   - Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site.

2. **Option B:**
   - Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site.

3. **Option C:**
   - Since the *p*-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site.

4. **Option D:**
   - Since the *p*-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site.

**Remember:**
- If the *p*-value ≤ significance level (0.10 in this case), reject the null hypothesis.
- If the *p*-value > significance level (0.10 in this case), do
Transcribed Image Text:### Understanding Standard Normal Distribution for Hypothesis Testing #### Step-by-Step Guide: **Step 1: Select one-tailed or two-tailed.** - Options: - One-tailed - Two-tailed **Step 2: Enter the test statistic. (Round to 3 decimal places.)** **Step 3: Shade the area represented by the *p*-value.** - This involves indicating the region under the normal curve that corresponds to the *p*-value. **Step 4: Enter the *p*-value. (Round to 3 decimal places.)** #### Example A chart illustrating a Standard Normal Distribution is provided. The curve peaks at the mean (0) and has symmetrical tails extending to -3 and 3. The height of the curve represents the probability density. #### Interpretation Based on the *p*-value: **(d) Based on your answer to part (c), choose what can be concluded, at the 0.10 level of significance, about the claim made in the school’s reports:** 1. **Option A:** - Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site. 2. **Option B:** - Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site. 3. **Option C:** - Since the *p*-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site. 4. **Option D:** - Since the *p*-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site. **Remember:** - If the *p*-value ≤ significance level (0.10 in this case), reject the null hypothesis. - If the *p*-value > significance level (0.10 in this case), do
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