2. What is the maximum amount of water which can be produced when 20.0 g of hydrogen is reacted with 30.0 g of oxygen? Which is the limiting reactant? Which is the excess reactant? How much of the excess reactant will be left over? H= 2*9.95%3D19.9 O= 2*.9377= 1.87 1.87*2=3.74

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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100%
.6262
6= 3.7
4.350-3.757=.593
.593 * 22.9898=13.63g
2. What is the maximum amount of water which can be produced when 20.0 g of
hydrogen is reacted with 30.0 g of oxygen? Which is the limiting reactant? Which
is the excess reactant? How much of the excess reactant will be left over?
H= 2*9.953D19.9
O= 2*.9377= 1.87
1.87*2=3.74
3. How many molecules of hydrogen gas will have been produced when the
reaction runs out between 4.32 g of aluminum metal and 17.65 g of hydrochloric
Transcribed Image Text:.6262 6= 3.7 4.350-3.757=.593 .593 * 22.9898=13.63g 2. What is the maximum amount of water which can be produced when 20.0 g of hydrogen is reacted with 30.0 g of oxygen? Which is the limiting reactant? Which is the excess reactant? How much of the excess reactant will be left over? H= 2*9.953D19.9 O= 2*.9377= 1.87 1.87*2=3.74 3. How many molecules of hydrogen gas will have been produced when the reaction runs out between 4.32 g of aluminum metal and 17.65 g of hydrochloric
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