2. Use Hess's law and the following reactions to calculate the enthalpy change for A-C AB CB AH-+20 kJ AH-+80 kJ

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**Transcription for Educational Website:**

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**Topic: Thermodynamics and Enthalpy Change**

**Problem 2: Using Hess's Law to Calculate Enthalpy Change**

Given Reactions:
1. \( A \rightarrow B \) with \(\Delta H = +20 \text{ kJ}\)
2. \( C \rightarrow B \) with \(\Delta H = +80 \text{ kJ}\)

**Objective:** Calculate the enthalpy change for the reaction \( A \rightarrow C \).

**Solution Approach:**

- Apply Hess's Law, which states that the total enthalpy change in a chemical reaction is the same regardless of the pathway taken, provided the initial and final conditions are the same.

- From Hess's Law, to find the enthalpy change for \( A \rightarrow C \), we need to reverse the second reaction: 

  \[
  B \rightarrow C \quad \text{with} \quad \Delta H = -80 \text{ kJ}
  \]

- Combine the pathways:

  \[
  \begin{align*}
  A \rightarrow B & \quad \Delta H = +20 \text{ kJ}, \\
  B \rightarrow C & \quad \Delta H = -80 \text{ kJ}.
  \end{align*}
  \]

- Total \(\Delta H\) for \( A \rightarrow C \):

  \[
  \Delta H = (+20 \text{ kJ}) + (-80 \text{ kJ}) = -60 \text{ kJ}
  \]

Thus, the enthalpy change for the reaction \( A \rightarrow C \) is \(-60 \text{ kJ}\).

---

**Source:** Problem Set 5 - Chapter 5

(Note: This transcription represents the specified section of the educational document. The content offers a clear explanation of applying Hess's Law in calculating enthalpy changes for chemical reactions.)

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Transcribed Image Text:**Transcription for Educational Website:** --- **Topic: Thermodynamics and Enthalpy Change** **Problem 2: Using Hess's Law to Calculate Enthalpy Change** Given Reactions: 1. \( A \rightarrow B \) with \(\Delta H = +20 \text{ kJ}\) 2. \( C \rightarrow B \) with \(\Delta H = +80 \text{ kJ}\) **Objective:** Calculate the enthalpy change for the reaction \( A \rightarrow C \). **Solution Approach:** - Apply Hess's Law, which states that the total enthalpy change in a chemical reaction is the same regardless of the pathway taken, provided the initial and final conditions are the same. - From Hess's Law, to find the enthalpy change for \( A \rightarrow C \), we need to reverse the second reaction: \[ B \rightarrow C \quad \text{with} \quad \Delta H = -80 \text{ kJ} \] - Combine the pathways: \[ \begin{align*} A \rightarrow B & \quad \Delta H = +20 \text{ kJ}, \\ B \rightarrow C & \quad \Delta H = -80 \text{ kJ}. \end{align*} \] - Total \(\Delta H\) for \( A \rightarrow C \): \[ \Delta H = (+20 \text{ kJ}) + (-80 \text{ kJ}) = -60 \text{ kJ} \] Thus, the enthalpy change for the reaction \( A \rightarrow C \) is \(-60 \text{ kJ}\). --- **Source:** Problem Set 5 - Chapter 5 (Note: This transcription represents the specified section of the educational document. The content offers a clear explanation of applying Hess's Law in calculating enthalpy changes for chemical reactions.) ---
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