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2. The equation of continuity and the equation of motion for one-dimensional flow of a Newtonian fluid yield av at p lay2 Os y s 0.15 IC: t= 0, V = 0.2 y BC 1: y 0, V 0.4 m/s BC 2: y = 0.15 m, V 0 at t > 0 at t>0 Find the velocity distribution after 10 seconds using the Explicit Method. Data : u = 0.045 kg/m.s, p= 995 kg/m3., Ay 0.025m and At = 5 s.

2. The equation of continuity and the equation of motion for one-dimensional flow of a Newtonian fluid yield av at p lay2 Os y s 0.15 IC: t= 0, V = 0.2 y BC 1: y 0, V 0.4 m/s BC 2: y = 0.15 m, V 0 at t > 0 at t>0 Find the velocity distribution after 10 seconds using the Explicit Method. Data : u = 0.045 kg/m.s, p= 995 kg/m3., Ay 0.025m and At = 5 s.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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2. The equation of continuity and the equation of motion for one-dimensional flow of a Newtonian fluid yield av at p lay2 IC: t 0, V - 0.2 - y 0s y s 0.15 BC 1: y = 0, V = 0.4 m/s at t > 0 %3D BC 2: y 0.15 m, V = 0 at t> 0 %3D Find the velocity distribution after 10 seconds using the Explicit Method. =D995kg/m3., Ay 0.025m and At = 5 s Data : u = 0.045 kg/m.s, p .
Transcribed Image Text:2. The equation of continuity and the equation of motion for one-dimensional flow of a Newtonian fluid yield av at p lay2 IC: t 0, V - 0.2 - y 0s y s 0.15 BC 1: y = 0, V = 0.4 m/s at t > 0 %3D BC 2: y 0.15 m, V = 0 at t> 0 %3D Find the velocity distribution after 10 seconds using the Explicit Method. =D995kg/m3., Ay 0.025m and At = 5 s Data : u = 0.045 kg/m.s, p .
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