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1. ( described as u = (0.5y – 50y²) m/s, and the unit of y is m. If the viscosity of the fluid is u = 1 x 10-3 N-s/m², what is the shear stress t at y = 0.005 m. Chapter 1: Fluid between a plate and a fixed surface shows Newtonian behavior. The velocity is Answer [ (A) T = 0.50 × 10-3 N/m² (B) T = 0.25 × 10-3 N/m² (C) T= 0.45 × 10-3 N/m² (D) T= 0 N/m? (E) Nove of the above %3D

1. ( described as u = (0.5y – 50y²) m/s, and the unit of y is m. If the viscosity of the fluid is u = 1 x 10-3 N-s/m², what is the shear stress t at y = 0.005 m. Chapter 1: Fluid between a plate and a fixed surface shows Newtonian behavior. The velocity is Answer [ (A) T = 0.50 × 10-3 N/m² (B) T = 0.25 × 10-3 N/m² (C) T= 0.45 × 10-3 N/m² (D) T= 0 N/m? (E) Nove of the above %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Fluid Mechanics Problem 1 and 2

 

1. ( described as u = (0.5y – 50y²) m/s, and the unit of y is m. If the viscosity of the fluid is µ = 1 x 10-³ N-s/m², what is the shear stress t at y = 0.005 m. Chapter 1: Fluid between a plate and a fixed surface shows Newtonian behavior. The velocity is Answer [ (A) T= 0.50 x 10-3 N/m² (B) T= 0.25 × 10-3 N/m² (C) T= 0.45 × 10-3 N/m? (D) T= 0 N/m? (E) Nove of the above 2. Chapter 3: The flow channel in the Figure is being steadily increased, oil particles in the channel along the center streamline have a velocity of V = (1– 0.5x)(1+ 0.5t) m/s, where x is in meters and t is in av + at DV seconds. Find the the acceleration magnitude [m/s?] when x = 0.0 m and t = 2.0 s. Note: a = = Dt V. VV Answer [. (A) a = 0.5 m/s? (В) а %3D —1.5 m/s? (C) a = 1.5 m/s? (D) a = 4.0 m/s? (E) a = -4.0 m/s² (F) None of above V
Transcribed Image Text:1. ( described as u = (0.5y – 50y²) m/s, and the unit of y is m. If the viscosity of the fluid is µ = 1 x 10-³ N-s/m², what is the shear stress t at y = 0.005 m. Chapter 1: Fluid between a plate and a fixed surface shows Newtonian behavior. The velocity is Answer [ (A) T= 0.50 x 10-3 N/m² (B) T= 0.25 × 10-3 N/m² (C) T= 0.45 × 10-3 N/m? (D) T= 0 N/m? (E) Nove of the above 2. Chapter 3: The flow channel in the Figure is being steadily increased, oil particles in the channel along the center streamline have a velocity of V = (1– 0.5x)(1+ 0.5t) m/s, where x is in meters and t is in av + at DV seconds. Find the the acceleration magnitude [m/s?] when x = 0.0 m and t = 2.0 s. Note: a = = Dt V. VV Answer [. (A) a = 0.5 m/s? (В) а %3D —1.5 m/s? (C) a = 1.5 m/s? (D) a = 4.0 m/s? (E) a = -4.0 m/s² (F) None of above V
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