2. The diameter of steel rods manufactured on two different extrusion machines is beinginvestigated. Two random samples of sizes n₁ = 9 and n₂ = 16 are selected, and thenåsample means and sample variances are è₁ = 10.5, s² = 0.5 and x₂ = 9.75, s² = 0.4,respectively. Assume that o² = 0² and that the data are drawn from a normaldistribution.(a) Test the hypothesis that the two means of the rod diameters are not equal using thecritical regions with a=0.05.(b) Test the hypothesis using the P-value with a=0.05.(c) Test the hypothesis using the 95% confidence interval for the difference in mean roddiameter.

Given that We have to test hypothesis for difference of two population means using a.. Critical…

Answered: 2. The diameter of steel rods…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of size 5 was collected from an unknown population 15 15 16 16 17 1. Use the table of expected z-scores (rounded to the nearest tenth) below to construct the normality plot with expected z-scores on the x-axis and the observations on the y-axis: 6 -1.3 -0.6 -0.2 0.2 0.6 1.3 5 -1.2 -0.5 0 0.5 1.2 -1 19 18 normal O not normal Clear All Draw: 17- 16- 14 T 15- رها 1 2 7 -1.4 -0.8 -0.4 0 0.4 0.8 1.4 8 -1.4 -0.9 -0.5 -0.2 0.2 0.5 0.9 1.4 9 -1.5 -0.9 -0.6 -0.3 0 0.3 0.6 0.9 1.5 2. Based on whether the pattern above is linear or not, in your opinion, was the sample drawn from a normal population or not?
Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributedpopulations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular μ μ1 μ2 n 33 33 x 0.78488 lb 0.80356 lb s 0.00444 lb 0.00744 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. i) What are the null alternative hypothesis? ii) What's the test statics? iii) What's the P-value? iv) State the conclusion vi) construct a confidence interval suitable suitable for testing the claim that the two samples are from populations with the same mean vii) Does the confidence interval…
A CNC (computer numerical control) machine produces iron automobile crankshafts. Samples are measured and the inner diameter are found to be 1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 0.99, 1.01, and 1.03 centimeters. For all computations, assume an approximately normal distribution. The sample mean and standard deviation for the given data are = 1.0056, and s =0.0246. Find a 99% confidence interval on the mean of diameter. Compute a 99% prediction interval on a measured diameter of a single crankshaft piece taken from the machine. Find the 99% tolerance limits that will contain most of the metal pieces produced by the CNC machine. O a. CI on the mean: 0.9781 <µ <1.0331. Prediction Interval: 0.9186 s Xp+151.0926. Tolerance Interval (0.8937 and 1.1175) O b. Insufficient data to compute. Missing the sample size n Oc CIon the mean: 0.9781 <µ<1.0331. Prediction Interval: 0.9186 s Xp+151.0926. Tolerance Interval (0.8937 and 1.1175). Insufficient data to compute for the Tolerance Interval Od. CI on…
Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. Diet Regular mu mu 1 mu 2 n 26 26 x overbar 0.79093 lb 0.81234 lb s 0.00433 lb 0.00753 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? A. Upper H 0 : mu 1 equalsmu 2 Upper H 1 : mu 1 greater thanmu 2 B. Upper H 0 : mu 1 equalsmu 2 Upper H 1 : mu 1 less thanmu 2 C. Upper H 0…
You wish to test the following claim (Ha) at a significance level of a 0.01. Ho:H1 = 42 Ha:H1 > H2 You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you also have no reason to believe the variances of the two populations are not equal. You obtain a sample of size n1 = 25 with a mean of M1 = 52.5 and a standard deviation of SD, = 9.1 from the first population. You obtain a sample of size n2 = 18 with a mean of M2 = 48.7 and a standard deviation of SD2 = 5.2 from the second population. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? For this calculation, use the conservative under-estimate for the degrees of freedom as mentioned in the textbook. (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the…
If Y is Normally distributed , and p(y < 170 ) = 0.14 p ( y > 200 ) = 0.03 then the values of the mean and variance of Y , respectively are
1. A study compared the number of tree species in unlogged forest plots to similar plots logged 8 years earlier. Independent random samples of both logged and unlogged plots were analyzed and the number of tree species was recorded. Tables 1 and 2 present the Shapiro-Wilk normality test for both types of forest plots and the Independent Samples t-test results. Use the information presented in these tables to answer the questions. Table 1: Tests of Normality Tests of Normality Kolmogorov-Smirnov Shapiro-Wilk Forest Plot Statistic df Sig. Statistic df Sig. Tree_Species Logged .181 12 .200 .936 12 .444 Unlogged .110 14 .200 .945 14 .480 *. This is a lower bound of the true significance. a. Lilliefors Significance Correction Table 2: Independent Samples Test Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means 95% Confidence Interval of the Difference Mean Std. Error F Sig. t df Sig. (2-tailed) Difference Difference Lower Upper Equal variances…
thill An experiment compares two different processes for producing steel plate. The measurements represent the thickness of the plate. The samples gave m = 8, X = 6.701, S1 = 0.108 n = 6, Y = 6.841, S2 = 0.155 %3D %3D Assume that the two populations are normal with equal variances, test Ho: H1 - H2 = 0 against H1 : µ1 - µ2#0 at a 0.05 significance level. 5.
Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. Diet Regular μ μ1 μ2 n 20 20 x 0.78646 lb 0.80233 lb s 0.00449 lb 0.00755 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? A. H0: μ1=μ2 H1: μ1≠μ2 B. H0: μ1=μ2 H1: μ1>μ2 C. H0: μ1≠μ2 H1: μ1<μ2 D. H0: μ1=μ2 H1: μ1<μ2 The test statistic, t, is nothing. (Round to two decimal places as needed.) The P-value is…
You have data drawn from a normal distribution with a known variance of 16. You set up the following NHST: • Ho: data follows a N(2, 4²) • HÃ: data follows a N(µ, 4²) where µ ‡ 2. Test statistic: standardized sample mean z. Significance level set to a = .05. You then collected n = 16 data points with sample mean 1.5. (a) Find the rejection region. Draw a graph indicating the null distribution and the rejection region. (b) Find the z-value and add it to your picture in part (a). (c) Find the p-value for this data and decide whether or not to reject Ho in favor of HA.
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 14 samples is 4.9 ppm with a variance of 1.2 Does the data support the claim at the 0.01 level? Assume the population distribution is approximately normal. Step 2 of 5 : Find the value of the test statistic. Round your answer to three decimal places.
The titanium content of steel is determined in two laboratories by means of atomic absorptionspectrometry. The following data were obtained: Lab 1 0.470 0.484 0.463 0.449 0.482 0.454 0.477 0.409 Lab 2 0.529 0.490 0.489 0.512 0.486 0.502 - - A. Determine the variance of the measurement data obtained in the two laboratories.B. Is there any significant difference between these variances?

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