You have data drawn from a normal distribution with a known variance of 16. You set upthe following NHST:• Ho: data follows a N(2, 4²)• HÃ: data follows a N(µ, 4²) where µ ‡ 2.Test statistic: standardized sample mean z.Significance level set to a = .05.You then collected n = 16 data points with sample mean 1.5.(a) Find the rejection region. Draw a graph indicating the null distribution and the rejectionregion.(b) Find the z-value and add it to your picture in part (a).(c) Find the p-value for this data and decide whether or not to reject Ho in favor of HA.

Answered: Image /qna-images/answer/f10114fc-40e9-40e1-be10-bbae3a00792a.jpg

Answered: You have data drawn from a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The hourly wages of a sample of 130 general workers are given below: mean = 60 range = 20 The coefficient of variation equals: Select one: - A. None of the other options O B. 30% OC. 54% D. 5.4% E. 0.30% Clear my choice variance = 324 M mode = 73 median = 74
You wish to test the claim that the first population mean is not equal to the second population mean at a significance level of α=0.02 . Ho:μ1=μ2 Ha:μ1≠μ2 You obtain the following two samples of data. Sample #1 Sample #2 67.1 64.2 32.7 49.0 63.8 54.8 63.5 54.1 65.6 54.8 40.5 58.7 39.4 43.1 72.5 73.1 70.2 71.2 68.1 73.1 79.7 67.3 66.5 61.7 62.9 76.5 What is the test statistic for this sample?test statistic = Round to 3 decimal places. What is the p-value for this sample?p-value = Use Technology Round to 4 decimal places. The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean. There is not sufficient…
Hello! I need answer for letter F only using Anderson-Darling test to support the normal distribution of the data.
A sample of size 8 was collected from an unknown population 0 1126 10 11 20 1. Use the table of expected z-scores (rounded to the nearest tenth) below to construct the normality plot with expected z-scores on the x-axis and the observations on the y-axis: 5 -1.2 -0.5 0 0.5 1.2 Clear All Draw: 22- 2 not normal normal 19 # 6 -1.3 -0.6 -0.2 0.2 0.6 1.3 7 -1.4 -0.8 -0.4 0 0.4 0.8 1.4 8 -1.4 -0.9 -0.5 -0.2 0.2 0.5 0.9 1.4 9 -1.5 -0.9 -0.6 -0.3 0 0.3 0.6 0.9 1.5 2. Based on whether the pattern above is linear or not, in your opinion, was the sample drawn from a normal population or not?
In this problem, we use your critical values table to explore the significance ofr based on different sample sizes. Critical Values for Correlation Coefficient r a = 0.05 =0.01 „A=0.05 a = 0.01 a = 0.05 a = 0.01 3. 1.00 1.00 13 0.53 0.68 23 0.41 0.53 4. 0.95 0.99 14 0.53 0.66 24 0.40 0.52 0.88 0.96 15 0.51 0.64 25 0.40 0.51 6. 0.81 0.92 16 0.50 0.61 26 0.39 0.50 0.75 0.87 17 0.48 0.61 27 0.38 0.49 8. 0.71 0.83 18 0.47 0.59 28 0.37 0.48 9. 0.67 0.80 19 0.46 0.58 29 0.37 0.47 10 0.63 0.76 20 0.44 0.56 30 0.36 0.46 11 0.60 0.73 21 0.43 0.55 12 0.58 0.71 22 0.42 0.54
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