2. Since a current-carrying wire is acted on by a magnetic force, it would seem possible to suspend such a wire at rest above the ground using the Earth's own magnetic field. In what direction would the current have to be in a long, straight wire located at the equator to perform such a feat? 1) Up 2) Down 3) East 4) West
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- 6. Two conducting wires are placed parallel to each other, 3.0 cm apart. A 2.6-A current flows through one of the wires, and a 5.2-A current flows through the other. What is the net magnetic field (magnitude and direction) 2.0 cm above the 2.6-A current wire? [Answer: B = 4.7 × 10-5 T © (out of page)] 2.0 cm 3.0 cm I= 2.6 A I = 5.2 A2. A wire of infinite length carries a current of 15A in a uniform magnetic field of magnitude 0.55T as indicated in the figure. (a) Find the force on a one meter length of the wire. (b) If the angle that the wire makes with the magnetic field is tripled, what happens to the direction of the force? Is the magnitude of the force tripled? Explain your answer. B 20Ords 8. An electron is moving through a magnetic field in a direction perpendicular to the field as shown below. The charge is moving with a speed of = 3.5x105 and it experiences a force of F = 1.79×10-13 N. English (US) What is the magnitude and direction of the magnetic field? The charge of an electron is qe = -1.6x10-19 C. v MacBook P 5
- 9. Consider the physical system shown below, which consists of two current-carrying wires each with a length of 71 cm. (a) If the net magnetic field at the point A is out of the page, is the force between the wires attractive or repulsive? Explain. (b) Calculate the magnitude of the force exerted by each wire on the other wire, given that the magnetic field at point A is out of the page with a magnitude of 0.21 T. 3.7 A Wire 1 22 cm Wire 2 11 cm2.- A straight wire has an electric current i = 20 A, the direction of the current is given by the vector u = 3.6 i + 4.2 k. The wire is inside a magnetic field B = 0.4i+0.6j. Calculate the total force on the wire1. In the diagram below, a charged particle enters a region of uniform magnètic field where B 0.6 T. The particle has an initial speed of 2.7 x 106 m/s. Keep in mind Newton's Second Law and recall the equation for centripetal acceleration: 1²/r. a. Ignore gravity and first determine the sign of the charged particle if it follows the trajectory of the dashed semicircle. b. Next, use the information given to derive an equation for the charge-to-mass ratio (q/m) of the particle in terms of the particle's speed, the magnitude of the magnetic field and the radius of the semicircle. c. Lastly, calculate the charge to mass ratio of this particle. 95.0 cm B
- 5. The magnitude of the magnetic field around a single current-carrying wire with current I, Hol is given be B = where 4= 47 × 10-7 T·m/A. The formula for the force on a single 2πη current-carrying wire with current I, is F = ILB, if the current is perpendicular to the magnetic field. What is the magnitude of the force between two parallel wires, each carrying a 1A current, if the wires are 10 m long and 2 m apart.Force on a Moving Charge: We observe that a moving charged particle experiences no magnetic force. From this we can definitely conclude that Group of answer choices A. either no magnetic field exists or the particle is moving perpendicular to the field. B. the particle is moving at right angles to the magnetic field. C. the particle must be moving parallel to the magnetic field. D. no magnetic field exists in that region of space. E. either no magnetic field exists or the particle is moving parallel to the field.10. Two wires carrying 3 A out of the page each are centered about the origin and separated by 8 cm along the x axis. a) Find the magnitude and direction of the magnetic field at a point +4 cm on the y axis. b) Find the magnitude and direction of the field at the origin. c) What is the magnitude of the force between the two wires? Attractive or Repulsive?