2. Remember, enthalpy is a state function, which allows us to calculate the overall change in enthalpy of a given reaction by summing up the changes from each step along the way. Set up a mathematical equation using variables only (no numbers) for how you determined the change in enthalpy of combustion of methane above. Use the numbers of each equation to keep them separate. Example: AH, (1) + AH, (2) = AHcombustion ΔΗ combustion = Next, compare your equation above with this new equation for calculating enthalpy of combustion using enthalpies of formation. Are they the same or different? What is different? What is the same? Can you mathematically rearrange your equation above to match? AH combustion= ΣΔΗ/products)-ΣΔΗ/reactants) [AHACO2)+2AH(H20)] – [2AH102)+AH(CH,)I AH combustion = [AH(CO2)+2AH(H20)] – [2AH(02)+AH(CH,)] AH combustion - %3D
2. Remember, enthalpy is a state function, which allows us to calculate the overall change in enthalpy of a given reaction by summing up the changes from each step along the way. Set up a mathematical equation using variables only (no numbers) for how you determined the change in enthalpy of combustion of methane above. Use the numbers of each equation to keep them separate. Example: AH, (1) + AH, (2) = AHcombustion ΔΗ combustion = Next, compare your equation above with this new equation for calculating enthalpy of combustion using enthalpies of formation. Are they the same or different? What is different? What is the same? Can you mathematically rearrange your equation above to match? AH combustion= ΣΔΗ/products)-ΣΔΗ/reactants) [AHACO2)+2AH(H20)] – [2AH102)+AH(CH,)I AH combustion = [AH(CO2)+2AH(H20)] – [2AH(02)+AH(CH,)] AH combustion - %3D
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
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![2. Remember, enthalpy is a state function, which allows us to calculate the overall change in enthalpy of a given
reaction by summing up the changes from each step along the way. Set up a mathematical equation using
variables only (no numbers) for how you determined the change in enthalpy of combustion of methane
above. Use the numbers of each equation to keep them separate. Example: AH (1) + AH, (2) = AH
combustion
ΔΗ
combustion
%3D
Next, compare your equation above with this new equation for calculating enthalpy of combustion using
enthalpies of formation. Are they the same or different? What is different? What is the same? Can you
mathematically rearrange your equation above to match?
AH combustion
ΣΔΗ/products)-ΣΔΗ/reactant3)
%3D
AH combustion
[AHACO2)+2AH(H20)] – [2AH(02)+AH(CH,))
%3D
AHcombustion = [AH(CO2)+2AH(H,0)] – [2AH(02)+AH¾CH,)]
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1b392c4-99f8-4c59-9caf-d50ca92ae3ad%2F08eb096a-a918-429c-8384-3c8b1c5d6498%2F3nblm16_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Remember, enthalpy is a state function, which allows us to calculate the overall change in enthalpy of a given
reaction by summing up the changes from each step along the way. Set up a mathematical equation using
variables only (no numbers) for how you determined the change in enthalpy of combustion of methane
above. Use the numbers of each equation to keep them separate. Example: AH (1) + AH, (2) = AH
combustion
ΔΗ
combustion
%3D
Next, compare your equation above with this new equation for calculating enthalpy of combustion using
enthalpies of formation. Are they the same or different? What is different? What is the same? Can you
mathematically rearrange your equation above to match?
AH combustion
ΣΔΗ/products)-ΣΔΗ/reactant3)
%3D
AH combustion
[AHACO2)+2AH(H20)] – [2AH(02)+AH(CH,))
%3D
AHcombustion = [AH(CO2)+2AH(H,0)] – [2AH(02)+AH¾CH,)]
%3D
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