2. Rank the ligands in order of their increasing effect on Act for Cr³+. Do this by looking at the energy of the light that the compounds absorb. You will have to make some judgment calls on the shades of colors. For example, if you are looking at a light green solution and an emerald green solution, you will have to think about which solution is absorbing the higher energy red light. In this case, the lighter green is absorbing a darker red than the emerald green, and the darker red will be lower in energy. 3. Rank the ligands in order of their increasing effect on Aoct for Co²+. 4. Fill in the following diagram listing the ligands in increasing order of Aoct- Use your rankings from both your chromium and your cobalt observations to make this single ranking. If the two individual rankings conflict, use your judgement based on which you felt gave you more definitive results or which one you have more confidence in.

2. Rank the ligands in order of their increasing effect on Act for Cr³+. Do this by looking at the energy of the light that the compounds absorb. You will have to make some judgment calls on the shades of colors. For example, if you are looking at a light green solution and an emerald green solution, you will have to think about which solution is absorbing the higher energy red light. In this case, the lighter green is absorbing a darker red than the emerald green, and the darker red will be lower in energy. 3. Rank the ligands in order of their increasing effect on Aoct for Co²+. 4. Fill in the following diagram listing the ligands in increasing order of Aoct- Use your rankings from both your chromium and your cobalt observations to make this single ranking. If the two individual rankings conflict, use your judgement based on which you felt gave you more definitive results or which one you have more confidence in.

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions

Section4.8: Stoichiometry Of Reactions In Aqueous Solution-titrations

Problem 2RC

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em1.png chem3.png Part 3: Q9 Average absorbance Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q9 Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q10 Flask 8 Flask 9 Flask 10 Flask 11 Q Part 3 0.146 [Fe] -0.002mol/L 0.166 volume 5.00mL 0.215 0.294 [FESCN mol/L) ✪ 4.59* 10 5.18*10* 6.64 x 10 9.08*10* [Fe(mol/L) 5.00 x 10 5.00*10* Y=3362x -0.0083 R¹ 0.9993 5.00 x 10 5.00*10* (Amounts of flask 8 (9 - 11's values are in the spreadsheet) 1:1 Ratio so, Molarity of Fe(NO3))3 = 0.2M Volume of Fe(NO3))3 = 5.00mL 71% Moles of Fe³= Molarity x volume(L) Moles of Fe = 0.2M × 0.005L = 1× 10-³mole 68% [SCN ](mol/ 4 x 10-4 5 x 10-4 7*10* 1*10* الخا chem2.png Concentration of Fe³ 9, X = mole of Fe³1x10³ mole Volume 0.0054 Ⓒ 8, Average absorbance for solution 8 (same for 9 - 11) Average absorbance for flask 8 = sum of all absorbances / number of readings (0.145 +0.147 +0.148) 3 Using equation of calibration curve's line(slope) of best fit, the average absorbances of the unknown concentrations to determine…
What is the concentration (in Molar) of a 1.00 cm (path length) sample that has an absorbance of 0.601? Concentration (M) Absorbancy 0.2 0.27 0.3 0.41 0.4 0.55 0.5 0.69
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calculate the [FESCN2+] using volumes of stock solutions. Presume that all of the SCN- ions react. Next, record the light absorbance values of each standard solution. Volume Volume Volume [FESCN2+] Absorbance Standard Fe(NO3)3 SCN- H2O sample (mL) (mL) (mL) 1 2.50 2.00 20.50 0.1811 2 2.50 1.50 21.00 0.3219 2.50 1.00 21.50 0.4981 4 2.50 0.50 22.00 0.6328 Stock [Fe(NO3)3] = 0.200 M, Stock [SCN-] = 0.0020 M. %3D
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em1.png Part 3: Q9 Average absorbance Flask 8 Flask 9 Flask 10 1:1 Ratio so, Flask 11 Part 3: Q Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q10 Flask 8 Flask 9 Flask 10 Flask 11 Part 3 0.146 0.166 [Fe] -0.002mol/L 0.215 0.294 [FESCN³mol/L) 4.59% 10 5.18*10* 6.64*10* 9.08*10* [FXmol/L) 5.00 *10* 5.00*10* Y=3362x-0.0083 R² = 0.9993 5.00*10* 5.00*10* (Amounts of flask 8 (9 - 11's values are in the spreadsheet) 71% volume 5.00mL Molarity of Fe(NO3))3 = 0.2M Volume of Fe(NO3))3 = 5.00mL Moles of Fe³= Molarity x volume(L) Moles of Fe¹ = 0.2M X 0.005L = 1x10-³mole x [SCN][mol/ 4x10 5×10-4 7x10 1×10 1 Concentration of Fe³ = mole of Fe³ Volume mole of Fe³1x10³ mole G.O05L 8, Average absorbance for solution 8 (same for 9 - 11) Average absorbance for flask 8 = sum of all absorbances / number of readings (0.145 +0.147 +0.148) 3 Using equation of calibration curve's line(slope) of best fit, the average absorbances of the unknown concentrations to determine [FeSCN-Jat equilibrium in solution 8:…