2. In Model 2, Example 1, solutions of sodium nitrate and potassium acetate are mixed together forming soluble products. If the solution were to be evaporated to dryness, name all of the compounds that might be found in the container.
Basics in Organic Reactions Mechanisms
In organic chemistry, the mechanism of an organic reaction is defined as a complete step-by-step explanation of how a reaction of organic compounds happens. A completely detailed mechanism would relate the first structure of the reactants with the last structure of the products and would represent changes in structure and energy all through the reaction step.
Heterolytic Bond Breaking
Heterolytic bond breaking is also known as heterolysis or heterolytic fission or ionic fission. It is defined as breaking of a covalent bond between two different atoms in which one atom gains both of the shared pair of electrons. The atom that gains both electrons is more electronegative than the other atom in covalent bond. The energy needed for heterolytic fission is called as heterolytic bond dissociation energy.
Polar Aprotic Solvent
Solvents that are chemically polar in nature and are not capable of hydrogen bonding (implying that a hydrogen atom directly linked with an electronegative atom is not found) are referred to as polar aprotic solvents. Some commonly used polar aprotic solvents are acetone, DMF, acetonitrile, DMSO, etc.
Oxygen Nucleophiles
Oxygen being an electron rich species with a lone pair electron, can act as a good nucleophile. Typically, oxygen nucleophiles can be found in these compounds- water, hydroxides and alcohols.
Carbon Nucleophiles
We are aware that carbon belongs to group IV and hence does not possess any lone pair of electrons. Implying that neutral carbon is not a nucleophile then how is carbon going to be nucleophilic? The answer to this is that when a carbon atom is attached to a metal (can be seen in the case of organometallic compounds), the metal atom develops a partial positive charge and carbon develops a partial negative charge, hence making carbon nucleophilic.
![Net Ionic Equations
Model 2: Net ionic reactions
When a soluble salt is placed in water, it separates into its ions. For example,
sodium chloride is soluble.
NaCl(s)
Nat (aq) + Cl(aq)
water
Example 1: Sodium nitrate reacts with potassium acetate in an aqueous
solution.
In double displacement (replacement) reactions, two ionic compounds react and
switch ions.
NaNO3 + KC₂H3O2 → KNO3 + NaC2H3O2
According to this "pencil and paper" reaction, potassium nitrate and sodium acetate
are produced. However, if this reaction is actually carried out in an aqueous
solution, nothing appears to happen.
If we investigate this system using the concept of a net ionic reaction we can see
why it appears that nothing happens. First, we write all of the compounds in the
equation, showing the ions that are formed when the reaction is carried out in
water.
Na+ (aq) + NO3(aq) + K+ (aq) + C₂H3O2 (aq) → K+ (aq) + NO3(aq) + Na+ (aq) + C2H3O2 (aq)
Next, we cross out any ions that are present on both the left (reactant) side and
right (product) side of the reaction.
N₂² (aq) + NO3(aq) + (aq) + C₂H5O2 (aq) →K(aq) + NO3(aq) +Na+ (aq) + C₂H5O2 (aq)
The ions we cross out, which are the same on both sides, are called spectator ions
(they are just "standing around watching", hence the term spectator).
Both of the compounds on the left hand side of the reaction (reactants) and the right
hand side of the reaction (products) are soluble. Therefore, no solid forms and no
reaction occurs. The ions are all simply floating around together in the solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78a96f4b-c4a7-4e44-95dd-3606c481f172%2Fae12c728-a74f-4f3b-a1d5-3bee8132e995%2Fgy934u_processed.jpeg&w=3840&q=75)
![2. In Model 2, Example 1, solutions of sodium nitrate and potassium acetate are
mixed together forming soluble products. If the solution were to be
evaporated to dryness, name all of the compounds that might be found in the
container.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78a96f4b-c4a7-4e44-95dd-3606c481f172%2Fae12c728-a74f-4f3b-a1d5-3bee8132e995%2Flhajthj_processed.jpeg&w=3840&q=75)
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