2. If F = 660 lb,60302 ft4 fto Position vector O to A, roAk} ft• Distance between O and A=ft• Direction (Unit) vector O to A, uOAk}o Force vector, F =k} lb• Direction angles of the force vector in degrees (a =• The component of the force acting parallel to the axis of the pole =lb

Answered: Image /qna-images/answer/66d07b8c-6dc1-48af-b045-68de0bdd1282.jpg

2. If F = 660 lb, 60 30 2 ft o Position vector O to A, rOA k} ft • Distance between O and A=| ft • Direction (Unit) vector O to A, uOA = i+ k} o Force vector, F = { k} lb +! • Direction angles of the force vector in degrees (a = BD • The component of the force acting parallel to the axis of the pole =D lb

2. If F = 660 lb, 60 30 2 ft o Position vector O to A, rOA k} ft • Distance between O and A=| ft • Direction (Unit) vector O to A, uOA = i+ k} o Force vector, F = { k} lb +! • Direction angles of the force vector in degrees (a = BD • The component of the force acting parallel to the axis of the pole =D lb

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

2. If F = 660 lb,
60
30
2 ft
4 ft
o Position vector O to A, roA
k} ft
• Distance between O and A=
ft
• Direction (Unit) vector O to A, uOA
k}
o Force vector, F =
k} lb
• Direction angles of the force vector in degrees (a =
• The component of the force acting parallel to the axis of the pole =
lb

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