2. Given the differential amplifier shown, RC1 5 ΚΩ Vcc=+15V Vout Vol RB1 1 ΚΩ Vs2 Vs1 VEE-15V Assume Q1 and Q2 are identical transistors with ß-hfe-100 and VBE=0.7V. (a) Determine hiel and hie2. (b) Determine the differential gains Ads (for single-ended) and Add (for double ended). (c) Determine the common-mode gains Acs (for single-ended) and Acd (for double ended). V02 RC₂ ' 5 ΚΩ RE • 7.5 ΚΩ RB2 1kQ

2. Given the differential amplifier shown, RC1 5 ΚΩ Vcc=+15V Vout Vol RB1 1 ΚΩ Vs2 Vs1 VEE-15V Assume Q1 and Q2 are identical transistors with ß-hfe-100 and VBE=0.7V. (a) Determine hiel and hie2. (b) Determine the differential gains Ads (for single-ended) and Add (for double ended). (c) Determine the common-mode gains Acs (for single-ended) and Acd (for double ended). V02 RC₂ ' 5 ΚΩ RE • 7.5 ΚΩ RB2 1kQ

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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QUESTION 5: A simplified class-AB output stage with BJTS is shown below. The circuit parameters are Vcc=15 V and R1 = 1900 2. For each transistor, Is= 9 x 10 ¬15 A. Determine the value of VBg that produces icn =ico=1 mA when vị= 0. What is the power dissipated in each transistor? Format : 2.7987275900068 VBB (V) Format : 62 Pon (mW)| (mW)| Format : 26 +Vcc icn VBB V BB 2 RL Qp lice -Vcc ww
3. Given the BJT amplifier circuit oVcc R1< Cc Rs Cc Vo Vs Io RE Ro' Vcc=18V, Rs=6802, RI=22KQ, Rp=2.2KN, RL=6.8KQ For transistor: Vbe=0.7V, ß=hfe=125 (a) Determine the DC voltage VCE- (b) Determine hie. (c) Determine the equivalent resistance Ro' (d) Determine the current gain Ais=lo/ls. (e) Determine the voltage gain Avs=Vo/Vs
34
(a) Using the hybrid-pi model with early voltage effect, compute the small signal voltage gain, Av, input resistance and output resistance for the CE BJT amplifier shown below. Q1. Vcc = 12 V B=100 VBE(ON) = 0.7V V = 100V R = 93.7k2 * R=6 k2 Vo Rs = 0.5 k2 C B E R,= 6.3 k2 Figure Q1(a)
A transistor amplifier circuit is biased so that the quiescent point is to the far left of the load line midpoint. What do you expect to occur when the input voltage begins to vary? O The output voltage will be distorted on the bottom because it will hit the lower limit for VCE before the input voltage arrives at its peak. The output voltage will be distorted on the top because it will hit the upper limit for VCE before the input voltage arrives at its peak. O The output voTransistor's output voltage will look like the input voltage amplified and inverted. The output voltage will be zero (flat).
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