2. Find the shaded area shown in the figure first by integrating with respect to x and next by integrating with respect to y. Follow all the steps from the class notes. Which method is easier? 2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Y = sqrt of x Y= (1/2) x
### Topic: Calculating the Area of a Region Bounded by Curves

#### Exercise Description
**Problem 2**: Find the shaded area shown in the figure first by integrating with respect to \( x \) and next by integrating with respect to \( y \). Follow all the steps from the class notes. Which method is easier?

#### Detailed Explanation

The provided graph displays two curves that form a bounded region with a shaded area. The curves are:
1. \( y = x \) in red.
2. \( y = \sqrt{x} \) in purple.

These curves intersect at the points \( (0,0) \) and \( (1,1) \), giving us the limits of integration for \( x \) from 0 to 1 and for \( y \) from 0 to 1.

##### Integrating with Respect to \( x \)
To calculate the shaded area by integrating with respect to \( x \), we use the expression for the area under a curve:
\[ \text{Area} = \int_{a}^{b} [f(x) - g(x)] \, dx \]
Where \( f(x) \) is the upper curve and \( g(x) \) is the lower curve.

Here,
- The upper curve: \( y = x \)
- The lower curve: \( y = \sqrt{x} \)

The shaded area \( A \) is:
\[ A = \int_{0}^{1} (x - \sqrt{x}) \, dx \]

##### Integrating with Respect to \( y \)
To integrate with respect to \( y \), we use the inverse functions for the integration:
\[ \text{Area} = \int_{c}^{d} [f(y) - g(y)] \, dy \]
Where \( f(y) \) is the right-most curve and \( g(y) \) is the left-most curve.

For this problem,
- The right-most curve: \( x = y^2 \)
- The left-most curve: \( x = y \)

The shaded area \( A \) is:
\[ A = \int_{0}^{1} (y - y^2) \, dy \]

##### Visual Representation
- The intersection points \( (0,0) \) and \( (1,1) \) are clearly marked.
- The area between these curves is shaded, indicating the region of interest.

#####
Transcribed Image Text:### Topic: Calculating the Area of a Region Bounded by Curves #### Exercise Description **Problem 2**: Find the shaded area shown in the figure first by integrating with respect to \( x \) and next by integrating with respect to \( y \). Follow all the steps from the class notes. Which method is easier? #### Detailed Explanation The provided graph displays two curves that form a bounded region with a shaded area. The curves are: 1. \( y = x \) in red. 2. \( y = \sqrt{x} \) in purple. These curves intersect at the points \( (0,0) \) and \( (1,1) \), giving us the limits of integration for \( x \) from 0 to 1 and for \( y \) from 0 to 1. ##### Integrating with Respect to \( x \) To calculate the shaded area by integrating with respect to \( x \), we use the expression for the area under a curve: \[ \text{Area} = \int_{a}^{b} [f(x) - g(x)] \, dx \] Where \( f(x) \) is the upper curve and \( g(x) \) is the lower curve. Here, - The upper curve: \( y = x \) - The lower curve: \( y = \sqrt{x} \) The shaded area \( A \) is: \[ A = \int_{0}^{1} (x - \sqrt{x}) \, dx \] ##### Integrating with Respect to \( y \) To integrate with respect to \( y \), we use the inverse functions for the integration: \[ \text{Area} = \int_{c}^{d} [f(y) - g(y)] \, dy \] Where \( f(y) \) is the right-most curve and \( g(y) \) is the left-most curve. For this problem, - The right-most curve: \( x = y^2 \) - The left-most curve: \( x = y \) The shaded area \( A \) is: \[ A = \int_{0}^{1} (y - y^2) \, dy \] ##### Visual Representation - The intersection points \( (0,0) \) and \( (1,1) \) are clearly marked. - The area between these curves is shaded, indicating the region of interest. #####
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