2. Fill in the for-loop below with the correct parameters to make room for the new value. saved Let's say that you have to write a function to insert an element into an ordered array. It takes an array A, a size, an index and a value. The value needs to be inserted at A[index] without losing values that are already in the array. // Assume that the index is found to be within array bounds and there is room to insert. for (int i - ?; ?; ?) A[i]=A[i-1]; A[index]=value; size++; 20:i< size:i++ index; i> 0; - O size; i> index; i-- size-1; i >- index; i--

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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### 2. Fill in the for-loop below with the correct parameters to make room for the new value.

Let's say that you have to write a function to insert an element into an ordered array. It takes an array `A`, a size, an index, and a value. The value needs to be inserted at `A[index]` without losing values that are already in the array.

```c
// Assume that the index is found to be within array bounds and there is room to insert.

for (int i = ?; ?; ?)
{
    A[i] = A[i-1];
}
A[index] = value;
size++;
```

#### Answer Choices:
- O 0; i < size; i++
- O index; i > 0; i--
- O size; i > index; i--
- O size-1; i >= index; i--

**Explanation:**

The task involves shifting elements to make room for a new value in a specific position (denoted by `index`) within the array `A`. Here are the choices for completing the for-loop:

1. **0; i < size; i++**: Incorrect, as it won't shift elements from the correct starting point for insertion.
2. **index; i > 0; i--**: Incorrect, as it would not cover all necessary shifts.
3. **size; i > index; i--**: **Correct**, it starts shifting from the end of the array until it reaches the specified index.
4. **size-1; i >= index; i--**: Also a possible correct choice for shifting elements to the right to make room for the new element.

### Key Point:
When inserting a value into an ordered array, elements from the position of insertion to the end of the used portion of the array must be shifted to the right. Select parameters in the loop that adequately handle this shifting operation to maintain order and make space for the new value.
Transcribed Image Text:### 2. Fill in the for-loop below with the correct parameters to make room for the new value. Let's say that you have to write a function to insert an element into an ordered array. It takes an array `A`, a size, an index, and a value. The value needs to be inserted at `A[index]` without losing values that are already in the array. ```c // Assume that the index is found to be within array bounds and there is room to insert. for (int i = ?; ?; ?) { A[i] = A[i-1]; } A[index] = value; size++; ``` #### Answer Choices: - O 0; i < size; i++ - O index; i > 0; i-- - O size; i > index; i-- - O size-1; i >= index; i-- **Explanation:** The task involves shifting elements to make room for a new value in a specific position (denoted by `index`) within the array `A`. Here are the choices for completing the for-loop: 1. **0; i < size; i++**: Incorrect, as it won't shift elements from the correct starting point for insertion. 2. **index; i > 0; i--**: Incorrect, as it would not cover all necessary shifts. 3. **size; i > index; i--**: **Correct**, it starts shifting from the end of the array until it reaches the specified index. 4. **size-1; i >= index; i--**: Also a possible correct choice for shifting elements to the right to make room for the new element. ### Key Point: When inserting a value into an ordered array, elements from the position of insertion to the end of the used portion of the array must be shifted to the right. Select parameters in the loop that adequately handle this shifting operation to maintain order and make space for the new value.
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