2. Calculate the enthalpy change for the reaction : C4H4 (9) + H2 (9) - C2H6 (g) Given the following data: i) C2H4 (9) + 3 O2 (g) → 2 CO2 (9) + 2 H20 (1) AH° = - 1410.9 kJ AH° = - 3119.4 kJ ii) 2 C2H6 (9) + 7 02 (9) - 4 CO2 (9) + 6 H20 (1) iii) 2 H2 (9) + O2 (9) 2 H20 (1) AH° = - 571.6 kJ 3. Calculate the standard enthalpy change for the reaction, C2H2 + 2 H2 (9) C2H6 (9) (9) Given that: i) 2 C2H2 (9) + 5 O2 (9)4 CO2 (9) + 2 H2O (1) ii) 2 C2H6 (9) + 7 02 (9)4 CO2 (9) + 6 H20 (1) iii) 2 H2 (g) + O2 (g) → AH° = - 2599 kJ AH° = - 3119 kJ AH° = - 572 kJ 2 H20 (1) The enthalpy of combustion of methane is -891 kJmol-1. Calculate the enthalpy of formation of methane if the enthalpy of formation of carbon dioxide and water are - 394 kJmol1 and -286 kJmol respectively. Chemical equation for formation of 4. methane: C(s) + 2H2(9) → CH4(9) Given: CH4(9) + 202(9) C(s) + O2(9) → CO2(9) H2(9) + 2 O2 H20 AH = -891 kJmol1 AH = -394 kJmol1 AH = -286 kJmol1 2H201) + CO2(9)

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
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2.
Calculate the enthalpy change for the reaction :
C4H4 (9) + H2 (9)
C2H6 (g)
Given the following data:
i)
C2H4 (9) + 3 O2 (9) → 2 CO2 (9) + 2 H2O (1)
AH° = - 1410.9 kJ
2 C2H6 (9) + 7 02 (9) →4 CO2 (9) + 6 H20 (1)
ii)
iii) 2 H2 (9) + O2 (g) 2 H2O (1)
AH° = - 3119.4 kJ
AH° = - 571.6 kJ
3.
Calculate the standard enthalpy change for the reaction,
C2H2 (g) + 2 H2 (9g) -
C2H6 (9)
Given that:
i)
2 C2H2 (9) + 5 02 (g) 4 CO2 (9) + 2 H2O (1)
AH° = - 2599 kJ
3119 kJ
ii)
2 C2H6 (9) + 7 02 (9) - 4 CO2 (9) + 6 H20 (1)
AH° =
iii) 2 H2 (9) + O2 (9) → 2 H2O ()
AH° = - 572 kJ
The enthalpy of combustion of methane is -891 kJmol-1. Calculate the enthalpy of
formation of methane if the enthalpy of formation of carbon dioxide and water are -
394 kJmol-1 and -286 kJmol respectively. Chemical equation for formation of
4.
methane:
C(s) + 2H2(9)
CH4(9)
Given:
AH = -891 kJmol-1
CH4(9) + 202(9) 2H2O() + CO2(g)
C(s) + Oz(g) → CO2(9)
H2(g) + 2 O2 - H20
AH = -394 kJmol-1
AH = -286 kJmol-1
Transcribed Image Text:2. Calculate the enthalpy change for the reaction : C4H4 (9) + H2 (9) C2H6 (g) Given the following data: i) C2H4 (9) + 3 O2 (9) → 2 CO2 (9) + 2 H2O (1) AH° = - 1410.9 kJ 2 C2H6 (9) + 7 02 (9) →4 CO2 (9) + 6 H20 (1) ii) iii) 2 H2 (9) + O2 (g) 2 H2O (1) AH° = - 3119.4 kJ AH° = - 571.6 kJ 3. Calculate the standard enthalpy change for the reaction, C2H2 (g) + 2 H2 (9g) - C2H6 (9) Given that: i) 2 C2H2 (9) + 5 02 (g) 4 CO2 (9) + 2 H2O (1) AH° = - 2599 kJ 3119 kJ ii) 2 C2H6 (9) + 7 02 (9) - 4 CO2 (9) + 6 H20 (1) AH° = iii) 2 H2 (9) + O2 (9) → 2 H2O () AH° = - 572 kJ The enthalpy of combustion of methane is -891 kJmol-1. Calculate the enthalpy of formation of methane if the enthalpy of formation of carbon dioxide and water are - 394 kJmol-1 and -286 kJmol respectively. Chemical equation for formation of 4. methane: C(s) + 2H2(9) CH4(9) Given: AH = -891 kJmol-1 CH4(9) + 202(9) 2H2O() + CO2(g) C(s) + Oz(g) → CO2(9) H2(g) + 2 O2 - H20 AH = -394 kJmol-1 AH = -286 kJmol-1
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