2. a. Considering the five compounds shown below, which one matches the given 'H NMR spectrum? Circle your answer. 2H Ꭰ 3H B IH ellle PPM E 6H b. Clearly match each peak in the NMR spectrum to a specific set of H atoms in your chosen structure. Use H₁, Hb, etc. for your labels on both your structure and the spectrum. c. List all of the compounds (A, B, C, D, E) that you would expect to have an IR peak at 1710 cm³¹? If none, write "NONE".

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### Interactive Learning Module: Identifying Compounds Using NMR Spectroscopy

#### Question 2

##### Part a
Consider the five compounds shown below. Identify which one matches the provided ^1H NMR spectrum and circle your answer.

**Compounds:**
- **A:** 2-methylbutane
- **B:** 3-methyl-2-pentanone
- **C:** 3,3-dimethylbutanoic acid
- **D:** 2,2-dimethylpropane
- **E:** 3-methyl-2-pentanal

**NMR Spectrum:**
The provided NMR spectrum has the following characteristics:
- **3H** peak around **1 ppm** (triplet)
- **6H** peak around **2.5 ppm** (singlet)
- **2H** peak around **4 ppm** (doublet)
- **1H** peak around **9.5 ppm** (singlet)

##### Part b
Match each peak in the NMR spectrum to a specific set of hydrogen atoms in your chosen compound. Use labels such as Ha, Hb, etc., for both your structure and the spectrum.

1. **6H** peak (singlet at ~2.5 ppm) - likely corresponds to two equivalent CH3 groups.
2. **3H** peak (triplet at ~1 ppm) - likely corresponds to a CH3 group.
3. **2H** peak (doublet at ~4 ppm) - likely corresponds to a CH2 group.
4. **1H** peak (singlet at ~9.5 ppm) - likely corresponds to an aldehyde proton (CHO).

**Note:** Based on these considerations, compound **C** (3,3-dimethylbutanoic acid) is the one that matches the provided ^1H NMR spectrum.

##### Part c
Identify which of the compounds (A, B, C, D, E) would exhibit an IR peak at 1710 cm^-1. If none, write "NONE."

- **B:** 3-methyl-2-pentanone
- **C:** 3,3-dimethylbutanoic acid
- **E:** 3-methyl-2-pentanal

Both compounds containing a carbonyl group (C=O) will exhibit an IR peak around 1710 cm^-1, which includes compounds **B**,
Transcribed Image Text:### Interactive Learning Module: Identifying Compounds Using NMR Spectroscopy #### Question 2 ##### Part a Consider the five compounds shown below. Identify which one matches the provided ^1H NMR spectrum and circle your answer. **Compounds:** - **A:** 2-methylbutane - **B:** 3-methyl-2-pentanone - **C:** 3,3-dimethylbutanoic acid - **D:** 2,2-dimethylpropane - **E:** 3-methyl-2-pentanal **NMR Spectrum:** The provided NMR spectrum has the following characteristics: - **3H** peak around **1 ppm** (triplet) - **6H** peak around **2.5 ppm** (singlet) - **2H** peak around **4 ppm** (doublet) - **1H** peak around **9.5 ppm** (singlet) ##### Part b Match each peak in the NMR spectrum to a specific set of hydrogen atoms in your chosen compound. Use labels such as Ha, Hb, etc., for both your structure and the spectrum. 1. **6H** peak (singlet at ~2.5 ppm) - likely corresponds to two equivalent CH3 groups. 2. **3H** peak (triplet at ~1 ppm) - likely corresponds to a CH3 group. 3. **2H** peak (doublet at ~4 ppm) - likely corresponds to a CH2 group. 4. **1H** peak (singlet at ~9.5 ppm) - likely corresponds to an aldehyde proton (CHO). **Note:** Based on these considerations, compound **C** (3,3-dimethylbutanoic acid) is the one that matches the provided ^1H NMR spectrum. ##### Part c Identify which of the compounds (A, B, C, D, E) would exhibit an IR peak at 1710 cm^-1. If none, write "NONE." - **B:** 3-methyl-2-pentanone - **C:** 3,3-dimethylbutanoic acid - **E:** 3-methyl-2-pentanal Both compounds containing a carbonyl group (C=O) will exhibit an IR peak around 1710 cm^-1, which includes compounds **B**,
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