2. A. Acetoin has the structure shown below. Carbon atoms exist at the corners of the sharp bends, such as where arrow C points (there are four carbon atoms in the structure). A .CH3 H3C ÓH B (i) add lone pairs of electrons where appropriate to the diagram. (ii) Give bond angle values for the points marked A, B, and C. Bond Angle A = Bond Angle B = Bond Angle C = (iii) Give the hybridization of the atoms marked A, B, and C. Hybridization A = Hybridization B = Hybridization C= (iv) Give the total number of sigma and pi bonds in the molecule. Number of sigma bonds = Number of pi bonds = (v) How many atoms in this molecule lie in the same plane?

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Chapter1: Chemical Foundations
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2. A. Acetoin has the structure shown below. Carbon atoms exist at the corners of the sharp bends, such as
where arrow C points (there are four carbon atoms in the structure).
A
CH3
H3C
B
(i) add lone pairs of electrons where appropriate to the diagram.
(ii) Give bond angle values for the points marked A, B, and C.
Bond Angle A =
Bond Angle B =,
Bond Angle C =
(iii) Give the hybridization of the atoms marked A, B, and C.
Hybridization A =
Hybridization B =
Hybridization C =
(iv) Give the total number of sigma and pi bonds in the molecule.
Number of sigma bonds =
Number of pi bonds =
(v) How many atoms in this molecule lie in the same plane?
Transcribed Image Text:2. A. Acetoin has the structure shown below. Carbon atoms exist at the corners of the sharp bends, such as where arrow C points (there are four carbon atoms in the structure). A CH3 H3C B (i) add lone pairs of electrons where appropriate to the diagram. (ii) Give bond angle values for the points marked A, B, and C. Bond Angle A = Bond Angle B =, Bond Angle C = (iii) Give the hybridization of the atoms marked A, B, and C. Hybridization A = Hybridization B = Hybridization C = (iv) Give the total number of sigma and pi bonds in the molecule. Number of sigma bonds = Number of pi bonds = (v) How many atoms in this molecule lie in the same plane?
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