2. A study was designed to compare the smoking habits of married men with those married women. A random sample of 240 men revealed that 180 smoked. A random sample of 220 women indicate that 54 smoked. At the 0.01 significance level does the evidence show that a higher proportion of men smoke? Solution: Step 1: State the hypotheses. Step 2: The level of significance and the critical region. and Step 3: Compute the value of z test for proportions. Step Decision rule, Step 5: Conclusion.

2. A study was designed to compare the smoking habits of married men with those married women. A random sample of 240 men revealed that 180 smoked. A random sample of 220 women indicate that 54 smoked. At the 0.01 significance level does the evidence show that a higher proportion of men smoke? Solution: Step 1: State the hypotheses. Step 2: The level of significance and the critical region. and Step 3: Compute the value of z test for proportions. Step Decision rule, Step 5: Conclusion.

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Description: 2. A study was designed to compare the smoking habits of married men with thosemarried women. A random sample of 240 men revealed that 180 smoked. A randomsample of 220 women indicate that 54 smoked. At the 0.01 significance level does theevidence s

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.77. You use a significance level of α=0.002α=0.002. H0:p=0.77H0:p=0.77 H1:p>0.77H1:p>0.77You obtain a sample of size n=324n=324 in which there are 256 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.77. There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have…
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The US Department of Energy reported that 45% of homes were heated by natural gas. A random sample of 348 homes in Oregon found that 156 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 1% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: P Test Statistic = =✓ ✓ OF H₁: P Based on the hypotheses, compute the following: p-value = 45 0° 45 OB vo
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n 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 25 30 35 40 45 50 60 70 80 90 100 n x=0.05 0.950 0.878 0.811 0.754 0.707 0.666 0.632 0.602 0.576 0.553 0.532 0.514 0.497 0.482 0.468 0.456 0.444 0.396 0.361 0.335 0.312 0.294 0.279 0.254 0.236 0.220 0.207 0.196 α = 0.05 α = 0.01 0.990 0.959 0.917 0.875 0.834 0.798 0.765 0.735 0.708 0.684 0.661 0.641 0.623 0.606 0.590 0.575 0.561 0.505 0.463 0.430 0.402 0.378 0.361 0.330 0.305 0.286 0.269 0.256 α = 0.01 NOTE: To test Ho: p=0 against H₁: p0, reject Ho if the absolute value of ris greater than the critical value in the table.
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6. A clinical trial is conducted comparing a new pain reliever for arthritis to a placebo. Participants are randomly assigned to receive the new treatment or a placebo and the outcome is pain relief within 30 minutes. The data are shown in Table 7–54. Is there a significant difference in the proportions of patients reporting pain relief? Run the test at a 5% level of significance.