2. A spherical insulator with a radius of 2 m has a volumetric charge density of p = A/r2, which would be a problem, except that a spherical hole with a radius of 0.5 m has been cut out of the middle of it. a. Find the total charge of the remaining hollow ball. b. Find the electric field at a distance of 1.0 m from the center of the sphere. Note: You will need to find the electric field for some arbitrary r < R, then plug in a value of r = 1.0 m into your final expression. c. Bonus: find the electric field at all points in space. This is easier than you think!
2. A spherical insulator with a radius of 2 m has a volumetric charge density of p = A/r2, which would be a problem, except that a spherical hole with a radius of 0.5 m has been cut out of the middle of it. a. Find the total charge of the remaining hollow ball. b. Find the electric field at a distance of 1.0 m from the center of the sphere. Note: You will need to find the electric field for some arbitrary r < R, then plug in a value of r = 1.0 m into your final expression. c. Bonus: find the electric field at all points in space. This is easier than you think!
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:2. A spherical insulator with a radius of 2 m has a volumetric charge density of p = A/r², which
would be a problem, except that a spherical hole with a radius of 0.5 m has been cut out of the
middle of it.
a. Find the total charge of the remaining hollow ball.
b. Find the electric field at a distance of 1.0 m from the center of the sphere.
Note: You will need to find the electric field for some arbitrary r < R, then plug in a value
of r = 1.0 m into your final expression.
c. Bonus: find the electric field at all points in space.
This is easier than you think!
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