Show all work please **Problem Description**Objects of masses \( m_1 = 4.00 \, \text{kg} \) and \( m_2 = 9.00 \, \text{kg} \) are connected by a light string that passes over a frictionless pulley, as shown in the figure. The object \( m_1 \) is held at rest on the floor, and \( m_2 \) rests on a fixed incline of \( \theta = 42.0^\circ \). The objects are released from rest, and \( m_2 \) slides 1.25 m down the slope of the incline in 3.85 s.**Diagram Explanation**The diagram illustrates a setup where:- \( m_1 \) sits on a horizontal surface connected via a string over a pulley to \( m_2 \).- \( m_2 \) is positioned on an incline angled at \( \theta = 42.0^\circ \).- The pulley is frictionless.**Questions**(a) Determine the acceleration of each object. (Enter the magnitude only.)- Acceleration: _______ \( \text{m/s}^2 \)(b) Determine the tension in the string. (Enter the magnitude only.)- Tension: _______ N(c) Determine the coefficient of kinetic friction between \( m_2 \) and the incline.- Coefficient of kinetic friction: _______**Instructions for Solving**1. Use the kinematic equation to calculate the acceleration down the slope: \[ s = ut + \frac{1}{2}at^2 \] Where \( s = 1.25 \, \text{m}, \, u = 0 \, \text{m/s}, \, t = 3.85 \, \text{s} \).2. Apply Newton's Second Law for both masses to relate tension and acceleration: - For \( m_1 \): \( T - m_1g = m_1a \) - For \( m_2 \): \( m_2g\sin\theta - T - \text{friction} = m_2a \)3. Calculate the frictional force using the normal force and solve for the coefficient of kinetic friction.This task involves analyzing forces on objects on an inclined plane and applying principles of dynamics and kinematics.

Name: Show all work please **Problem Description**Objects of masses \( m_1 =
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: Show all work please **Problem Description**Objects of masses \( m_1 = 4.00 \, \text{kg} \) and \( m_2 = 9.00 \, \text{kg} \) are connected by a light string that passes over a frictionless pulley, as shown in the figure. The object \( m_1 \) is held