2. A Blue has a constant acceleration of 3.00 m/s² i and is initially at rest. A Red object has an initial velocity of -5.00 m/s i and is initially 100 m in front of the Blue object. a) How long does it take to Blue object to move 50.0 m from its initial position? Blue a =3.00 is BLUE RED Vi = 0 Vi = -5.00 Dx=50 Ax=2at?+Vit G0 = (3 )t?+ Ot 50=1.5E2 %3D t=5.775 b) What acceleration should the Red object have if it is to collide with the Blue object upon traveling 50.0 m towards it? Note that the Red object must move in the -x direction. 100m RED Blue 4x = 50m -- 2. a =3.00ms Vi = -5.oom 4X =5O=same 4x=50 sOme 4x =a+?+ vit 2. 50=7a c) If the Red object actually has an acceleration of 1.50 m/s?, what is the distance between the two objects at t = 3.00 seconds? %3D △メレー -attvit BしVE a = 1.50ms² a = 3.00m,s? Arp =(3)(3)"to = 13.5 AKB 0=13.5 Ax =?= same Ź (1.50)(3)°+ (- 5)(3) %3D t= 3 s %3D Ax = ?same ViニーS m) -8.25 |4-Axpl= ムx8-△xp1 AXB 13.5-(-8.2) ムxニ21.8m 100-21.8=D78.2 d) If the Red object actually has an acceleration of 1.50 m/s?, at what time are their speeds the same? VF= at + Vi %3D Blue 2. aニ3.00m? a = 1.50mis Vi = O Vi=-5m/s VE= 150t + (-s) t= same t= same %3D %3D
2. A Blue has a constant acceleration of 3.00 m/s² i and is initially at rest. A Red object has an initial velocity of -5.00 m/s i and is initially 100 m in front of the Blue object. a) How long does it take to Blue object to move 50.0 m from its initial position? Blue a =3.00 is BLUE RED Vi = 0 Vi = -5.00 Dx=50 Ax=2at?+Vit G0 = (3 )t?+ Ot 50=1.5E2 %3D t=5.775 b) What acceleration should the Red object have if it is to collide with the Blue object upon traveling 50.0 m towards it? Note that the Red object must move in the -x direction. 100m RED Blue 4x = 50m -- 2. a =3.00ms Vi = -5.oom 4X =5O=same 4x=50 sOme 4x =a+?+ vit 2. 50=7a c) If the Red object actually has an acceleration of 1.50 m/s?, what is the distance between the two objects at t = 3.00 seconds? %3D △メレー -attvit BしVE a = 1.50ms² a = 3.00m,s? Arp =(3)(3)"to = 13.5 AKB 0=13.5 Ax =?= same Ź (1.50)(3)°+ (- 5)(3) %3D t= 3 s %3D Ax = ?same ViニーS m) -8.25 |4-Axpl= ムx8-△xp1 AXB 13.5-(-8.2) ムxニ21.8m 100-21.8=D78.2 d) If the Red object actually has an acceleration of 1.50 m/s?, at what time are their speeds the same? VF= at + Vi %3D Blue 2. aニ3.00m? a = 1.50mis Vi = O Vi=-5m/s VE= 150t + (-s) t= same t= same %3D %3D
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Answer Part C). If the red object has an acceleration of 1.50 m/s^2, what is the distance between the two objects at t= 3.00 seconds?
Transcribed Image Text:2. A Blue has a constant acceleration of 3.00 m/s² i and is initially at rest. A Red
object has an initial velocity of -5.00 m/s i and is initially 100 m in front of the
Blue object.
a) How long does it take to Blue object to move 50.0 m from its initial position?
Blue
a =3.00 is
BLUE
RED
Vi = 0
Vi = -5.00
Dx=50
Ax=2at?+Vit
G0 = (3 )t?+ Ot
50=1.5E2
%3D
t=5.775
b) What acceleration should the Red object have if it is to collide with the Blue
object upon traveling 50.0 m towards it? Note that the Red object must move in the
-x direction.
100m
RED
Blue
4x = 50m
--
2.
a =3.00ms
Vi = -5.oom
4X =5O=same
4x=50 sOme
4x =a+?+ vit
2.
50=7a
Transcribed Image Text:c) If the Red object actually has an acceleration of 1.50 m/s?, what is the distance
between the two objects at t = 3.00 seconds?
%3D
△メレー
-attvit
BしVE
a = 1.50ms²
a = 3.00m,s?
Arp =(3)(3)"to = 13.5
AKB
0=13.5
Ax =?= same
Ź (1.50)(3)°+ (- 5)(3)
%3D
t= 3 s
%3D
Ax = ?same
ViニーS m)
-8.25
|4-Axpl=
ムx8-△xp1
AXB
13.5-(-8.2)
ムxニ21.8m
100-21.8=D78.2
d) If the Red object actually has an acceleration of 1.50 m/s?, at what time are their
speeds the same?
VF= at + Vi
%3D
Blue
2.
aニ3.00m?
a = 1.50mis
Vi = O
Vi=-5m/s
VE= 150t + (-s)
t= same
t= same
%3D
%3D
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