A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by = [5.00 m/s- (0.0180 m/s³)t² i + [2.00 m/s + (0.550 m/s²)t]j. ▼ v = 7.00 Submit Previous Answers ✓ Correct Part D What is the direction (in degrees counterclockwise from +-axis) of the velocity of the car at t = 6.50 s? Express your answer in degrees. 0 52.70 Submit Previous Answers ✓ Correct Part E What is the magnitude of the acceleration of the car at t = 6.50 s? Express your answer with the appropriate units. a=0.357 m S KING ? Check the units used in your calculation; the numerical value you reached does not appear to have dimensions of acceleration. No credit lost. Try again. Submit Previous Answers Request Answer

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a
function of time is given by = [5.00 m/s - (0.0180 m/s³)t²] i +
[2.00 m/s + (0.550 m/s²)t]j.
v = 7.00
Submit Previous Answers
✓ Correct
Part D
What is the direction (in degrees counterclockwise from +-axis) of the velocity of the car at t = 6.50 s?
Express your answer in degrees.
0₂ = 52.7 °
Submit
✓
Part E
a =
Previous Answers
Correct
What is the magnitude of the acceleration of the car at t = 6.50 s?
Express your answer with the appropriate units.
0.357
Submit
μÀ
m
S
?
Check the units used in your calculation; the numerical value you reached does not appear to have dimensions of acceleration.
No credit lost. Try again.
Previous Answers Request Answer
Transcribed Image Text:A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by = [5.00 m/s - (0.0180 m/s³)t²] i + [2.00 m/s + (0.550 m/s²)t]j. v = 7.00 Submit Previous Answers ✓ Correct Part D What is the direction (in degrees counterclockwise from +-axis) of the velocity of the car at t = 6.50 s? Express your answer in degrees. 0₂ = 52.7 ° Submit ✓ Part E a = Previous Answers Correct What is the magnitude of the acceleration of the car at t = 6.50 s? Express your answer with the appropriate units. 0.357 Submit μÀ m S ? Check the units used in your calculation; the numerical value you reached does not appear to have dimensions of acceleration. No credit lost. Try again. Previous Answers Request Answer
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