How was it solvedAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms 2.A 70-Vac source has the following waveform. Determine:a.Vpkb. Vpk-pkC.Vrmsd. Periode.Frequencyf. Angular Velocityg.Phase Angleh.i.j.equation of the waveform (in time domain)the instantaneous voltage when t = 120 msthe angle (1st occurrence) after t = 0 when thevoltage is +80 Vk.the time (2nd occurrence) after t = 0 when thevoltage is -10 V- 50 ms -M180 VФ -

The RMS value of the source is given as 70V and the half cycle duration is given as 50ms. The…

Answered: 2. A 70-Vac source has the following…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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How was it solved

Answers:

a. 98.9949 V
b. 197.9899 V
c. 70 V
d. 100 ms
e. 10 Hz
f. 20π rad/sec
g. 125.0876°
h. v(t) = 98.9949sin(20πt + 125.0876°)
i. -29.0880 V
j. 0.99959°
k. 63.643 ms

2.
A 70-Vac source has the following waveform. Determine:
a.
Vpk
b. Vpk-pk
C.
Vrms
d. Period
e.
Frequency
f. Angular Velocity
g.
Phase Angle
h.
i.
j.
equation of the waveform (in time domain)
the instantaneous voltage when t = 120 ms
the angle (1st occurrence) after t = 0 when the
voltage is +80 V
k.
the time (2nd occurrence) after t = 0 when the
voltage is -10 V
- 50 ms -
M
180 V
Ф -

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